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KengaRu [80]
3 years ago
10

An astronaut on another planet drops a 1-kg rock from rest and finds that it falls a vertical distance of 2.5 meters in one seco

nd. on this planet, the rock has a weight of: (hint: use d= 1/2 g t^2 to find g; then use w = mg to find weight.)
Physics
2 answers:
amid [387]3 years ago
8 0

Answer:

Weight = 5 N

Explanation:

As we know that rock falls a distance of 2.5 m in one second so now we can use kinematics to find the acceleration of the rock

d = \frac{1}{2}gt^2

here we know

d = 2.5 m

t = 1 s

now from above equation we know

2.5 = \frac{1}{2}g(1)^2

g = 5 m/s^2

So here the weight of the rock is given as

W = mg

W = 1\times 5

W = 5 N

kow [346]3 years ago
4 0
X=.5(a)t^2 can be used: 2.5m=.5(g)(1), g=5m/s^2. 
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A 2.00-kg rock has a horizontal velocity of magnitude 12.0 m>s when it is at point P in Fig. E10.35. (a) At this instant, wha
zaharov [31]

Answer:

(A) L = 115.3kgm²/s

(B) dL/dt = 94.1kgm²/s²

Explanation:

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