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3 years ago

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An astronaut on another planet drops a 1-kg rock from rest and finds that it falls a vertical distance of 2.5 meters in one seco

nd. on this planet, the rock has a weight of: (hint: use d= 1/2 g t^2 to find g; then use w = mg to find weight.)

2 answers:

amid [387]3 years ago

8 0

Answer:

Weight = 5 N

Explanation:

As we know that rock falls a distance of 2.5 m in one second so now we can use kinematics to find the acceleration of the rock

$d = \frac{1}{2}gt^2$

here we know

d = 2.5 m

t = 1 s

now from above equation we know

$2.5 = \frac{1}{2}g(1)^2$

$g = 5 m/s^2$

So here the weight of the rock is given as

$W = mg$

$W = 1\times 5$

$W = 5 N$

kow [346]3 years ago

4 0

X=.5(a)t^2 can be used: 2.5m=.5(g)(1), g=5m/s^2.

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A long thin uniform rod of length 1.50 m is to be suspended from a frictionless pivot located at some point along the rod so tha

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Answer:

0.087 m

Explanation:

Length of the rod, L = 1.5 m

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$T = 2\pi \sqrt{\frac{I}{mgd}}$ .... (1)

where, I is the moment of inertia of the rod about the pivot point and g is the acceleration due to gravity.

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Substituting the values in equation (1)

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trasher [3.6K]

Answer:

$\frac{F}{W} = 9.37 \times 10^{-4}$

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