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KengaRu [80]
3 years ago
10

An astronaut on another planet drops a 1-kg rock from rest and finds that it falls a vertical distance of 2.5 meters in one seco

nd. on this planet, the rock has a weight of: (hint: use d= 1/2 g t^2 to find g; then use w = mg to find weight.)
Physics
2 answers:
amid [387]3 years ago
8 0

Answer:

Weight = 5 N

Explanation:

As we know that rock falls a distance of 2.5 m in one second so now we can use kinematics to find the acceleration of the rock

d = \frac{1}{2}gt^2

here we know

d = 2.5 m

t = 1 s

now from above equation we know

2.5 = \frac{1}{2}g(1)^2

g = 5 m/s^2

So here the weight of the rock is given as

W = mg

W = 1\times 5

W = 5 N

kow [346]3 years ago
4 0
X=.5(a)t^2 can be used: 2.5m=.5(g)(1), g=5m/s^2. 
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Answer:

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Explanation:

Objects               Mass                                Force

1                            10 kg                               4 N              

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Acceleration of object 1,

a_1=\dfrac{F_1}{m_1}\\\\a_1=\dfrac{4}{10}\\\\a_1=0.4\ m/s^2

Acceleration of object 2,

a_2=\dfrac{F_2}{m_2}\\\\a_2=\dfrac{20}{0.1}\\\\a_2=200\ m/s^2

Acceleration of object 3,

a_3=\dfrac{F_3}{m_3}\\\\a_3=\dfrac{4}{0.01}\\\\a_3=400\ m/s^2

Acceleration of object 4,

a_4=\dfrac{F_4}{m_4}\\\\a_4=\dfrac{20}{1}\\\\a_3=20\ m/s^2

It is clear that the acceleration of object 3 is 400\ m/s^2 and it is greatest of all. So, the correct option is (3).

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