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2 years ago

12

Pls help me!!!!solve this question

1 answer:

nasty-shy [4]2 years ago

3 0

(11k^4 - 4m) + (-2k^4 - 15m)
Add -2k^4 to 11k^4. This would be the same as subtracting 2k^4 from 11k^4
9k^4 - 4m - 15m
Add -15m to -4m. This would be the same as subtracting 15m from -4m
Final Answer: 9k^4 - 19m

Word Form: Nine times the variable k to the forth power minus nineteen times the variable m.

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Solve the equation to find where the treste ground levelEnter your answers from least to greatest and round to the nearest The m

DaniilM [7]

Answer:

The trestle meets ground level at 0.875 units and 9.125 units

Step-by-step explanation:

Poorly formatted question.

The given equation is:

$y = -x^2 + 10x - 8$

Required

The point where the trestle gets to the ground level

To do this, we set $y = 0$

So, we have:

$-x^2 + 10x - 8 = 0$

Multiply through by -1

$x^2 -10x + 8 = 0$

Solve using quadratic formula:

$x= \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

Where:

$a = 1; b =-10; c = 8$

So, we have:

$x= \frac{-(-10) \± \sqrt{(-10)^2 - 4*1*8}}{2*1}$

$x= \frac{-(-10) \± \sqrt{68}}{2*1}$

$x= \frac{-(-10) \± 8.25}{2}$

$x= \frac{10 \± 8.25}{2}$

Solve the fraction

$x= 5 \± 4.125$

Split

$x= 5 + 4.125\ or\ x= 5 - 4.125$

$x= 9.125\ or\ x= 0.875$

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2 years ago

Find two positive consecutive odd integers such that square of the smaller integer is 10 more than the larger integer

Otrada [13]

Let $2n+1$ be the smaller integer. The larger integer is then $2n+3$ , and we have

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$\implies4n^2+2n-12=0$

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$\implies 2n-3=0\text{ or }n+2=0$

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We omit $n=-2$ , since $2(-2)+1=-3$ is negative.

Then for $n=\dfrac32$ we find $2\left(\dfrac32\right)+1=4$ , but this is not odd.

There are no consecutive odd integers that satisfy the given condition!

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pickupchik [31]

No this is the awnser-3x+y=2

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Answer:

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Step-by-step explanation:

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