If your weight is 100N and you run up a flight of stairs that is 6 m high and it takes
1 answer:
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<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2>
mass = 4 kg
velocity = 5 m/s^2
<h3 /><h3>Orange truck:</h3>Mass= 2kg
Velocity = 7m/s^2
<h3 /><h3>Grey Car:</h3>mass = 6 kg
velocity = 4m/s^2
<h3 /><h3>Green Car:</h3>Mass = 8 kg
Velocity = 3 m/s^2
<h2>_____________________________________</h2><h2>SOLUTION:</h2>By the equation of kinetic energy,
K.E =
Where,
K.E is kinetic energy
m is mass
v is velocity
<h2>_____________________________________</h2><h3>Kinetic energy of Blue car:</h3>
Directly substitute the variables in the equation,
K.E =
Simplify the equation,
K.E = 50 J
<h2>_____________________________________</h2><h3>Kinetic Energy of Silver Car:</h3>
Directly substitude the variable in the equation,
K.E =
Simplify the equation,
K.E = 48J
<h2>_____________________________________</h2><h3>Kinetic Energy of Green Car:</h3><h3 />Substitute the variables in the equation,
K.E =
Simplify the Equation,
K.E = 36J
<h2>_____________________________________</h2><h3>Kinetic Energy of Orange Truck:</h3><h3 />Substitute the variable,
K.E =
Simplify the equation,
K.E = 49J
<h2>_____________________________________</h2>As you can see that the highest value of kinetic energy is of Blue SUV thus it will be out answer.
<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h3 /><h3 /><h3 /><h3 /><h2 /><h2 />The required torque at the axle, is given by the difference between the
moments of the applied forces.
The torque required is <u>19.62 N·m counterclockwise</u>
Reasons:
The given parameters are;
Mass of the disk, m = 5.0 kg
Location of the axle = Half the radius of the disk
Diameter of the disk, D = 40 cm = 0.4 m
Applied mass, 0.1 m from the axle = 15 kg
Applied mass, 0.3 m from the axle = 10 kg
Required:
Magnitude of torque at the axle that prevent the disk from rotating
Solution:
Torque needed = Clockwise moment - Counterclockwise moment
Clockwise moment = (10 kg × 0.3 m + 5 kg × 0.1 m) × 9.81 m/s² = 34.335 N·m
Counterclockwise moment = 15 kg × 0.1 m × 9.81 m/s² = 14.715 N·m
τ + Counterclockwise moment = Clockwise moment
τ + 14.715 N·m = 34.335 N·m
Torque required, τ = 34.335 N·m - 14.715 N·m = 19.62 N·m
Torque required, τ = <u>19.62 N·m counterclockwise</u>
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<em>The probable question drawing obtained from a similar question online is attached</em>
