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3 years ago

WILL MARK BRAINLEST PLEASE HELP

Engineering

1 answer:

TEA [102]3 years ago

6 0

I put

People who pursue a career in the creative imaging fields have qualities like a good imagination, creativity, open minds, good with ideas, and handling situations. If you enter that field, you need imagination to create things and an open mind to be open to all creations. You need good ideas to make good thing that will work.

please don't plagiarise tho, re-word it.

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At what times should you use your headlights?

SVETLANKA909090 [29]

Answer:

Headlights are required to be used 1/2 hour after sunset to 1/2 hour before sunrise, when windshield wipers are being used, when visibility is less than 1000 feet, or when there is insufficient light or adverse weather.

Explanation:

hope this helps

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3 years ago

Read 2 more answers

Write a loop to print all elements in hourly_temperature. Separate elements with a -> surrounded by spaces. Sample output for

ELEN [110]

The answer & explanation for this question is given in the attachment below.

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3 years ago

What is your understanding and opinion on the validity of the stand-by equipment maintenance requirement?

Fed [463]

Answer:

The stand-by equipment is technically required in case where the we need some urgent equipment for the purpose of maintenance in emergency and if the other equipment system get fails. the term stand by means backup equipment and component.

In the reliability engineering, we always need to provide an extra equipment or component in case of emergency. It is basically used so that it does not affect any type of productivity in the organization. It is also increase the redundancy of the equipment.

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3 years ago

Series and parrarel circuts combination a. Find the currents I1, I2, I3, I4, I5, and I6. a 5 k R1 = 1 k R7 = 2 k I1 I428 V 6 k R

satela [25.4K]

Answer:

Explanation:

R1 = 1 k; R2 = 1k; R3 = 3k; R4 = 6k; R5 = 5k; R6 = 6k and R7 = 2k

Vt = 428V

The series and parallel circuit combination is as follow:

(R6║R7 + R5) + R4 + R3║R2 + R1

(6*2/6 + 2) + 5 = 13/ k

(13/2*6/13/6 + 6) = 78/31k

78/3 + 3 = 171/3 = 57k

57k║R2 = 57k║1k = 57/58k + R1 = (57/58 + 1)k = 115/58k = 2k

It = Vt/2k = 428/2000 = 0.2A

∴ I1 = 0.2A

I1 = I2 + I3

Using current divider rules to obtain I2 and I3

∴ I2 = I1 X (I2/I2 + I3) = 0.2 X ( 1/4) = 0.05A

and I3 = I1 X (I3/I2 + I3) = 0.2 X (3/4) = 0.15A

I3 = I4 + I5, using current divider

I4 = I3 X (I4/I4 + I5) = 0.15 X (6/6 + 5) = 0.08

I5 = 0.15 - 0.08 = 0.07A

I5 = I6 + I7, using current divider

I6 = I5 X (I6/I6 + I7) = 0.07 X (6/6 + 2) = 0.05A

I7 = 0.07 - 0.05 = 0.02A

8 0

3 years ago

Explain why failure of this garden hose occurred near its end and why the tear occurred along its length. Use numerical values t

alukav5142 [94]

Answer:

hoop stress
longitudinal stress
material used

all this could led to the failure of the garden hose and the tear along the length

Explanation:

For the flow of water to occur in any equipment, water has to flow from a high pressure to a low pressure. considering the pipe, water is flowing at a constant pressure of 30 psi inside the pipe which is assumed to be higher than the allowable operating pressure of the pipe. but the greatest change in pressure will occur at the end of the hose because at that point the water is trying to leave the hose into the atmosphere, therefore the great change in pressure along the length of the hose closest to the end of the hose will cause a tear there. also the other factors that might lead to the failure of the garden hose includes :

hoop stress ( which acts along the circumference of the pipe):

αh = $\frac{PD}{2T}$ EQUATION 1