Solve the inequality. 6 >= -3/2d
1 answer:
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Answer:
The number of same-day tickets sold is 15
The number of advance ticket sold is 20
Step-by-step explanation:
Given as :
The cost of each Advance ticket = $35
The cost of each same-day ticket = $30
The total cost of the tickets sold = $1150
The total number of tickets sold = 35
Let The number of advance ticket sold = a
And The number of same-day ticket sold = s
Now, According to question
The total number of tickets sold =The number of advance ticket sold + The number of same-day ticket sold
I.e a + s = 35 .....A
The total number of tickets sold = The cost of each Advance ticket × The number of advance ticket sold + The cost of each same-day ticket × The number of same-day ticket sold
I.e $35 a + $30 s = $1150
or, 35 a + 30 s = 1150 .......B
Now, solving eq A and B
35 × ( a + s) - ( 35 a + 30 s ) = 35 × 35 - 1150
or, ( 35 a - 35 a ) + ( 35 s - 30 s ) = 1225 - 1150
or, 0 + 5 s = 75
∴ s =
I.e s = 15
So, The number of same-day tickets sold = s = 15
Put the value of s in Eq A
So, a + 15 = 35
∴ a = 35 - 15
I.e a = 20
So, The number of advance ticket sold = a = 20
Hence The number of same-day tickets sold is 15
And The number of advance ticket sold is 20 Answer
Use this formula.
and solution is:［（18！）/（6！×（18-6）！）］×（1/2）^6×（1-1/2）^（18-6）≈0.0781604
7.8%
and solution is:［（18！）/（6！×（18-6）！）］×（1/2）^6×（1-1/2）^（18-6）≈0.0781604
7.8%