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3 years ago

Help! Need it ASAP! Is steam and vapour different? If they are then how are they different?

Chemistry

2 answers:

Alexxx [7]3 years ago

8 0

Answer:

Explanation:

Water vapor is when water molecules are present in the air, while steam is water heated to the point that it turns into gas. In simplified science, both are referred to as the gaseous state of water. Steam is usually white or translucent in nature, while water vapor can be clear or translucent.

Steam is simply, water vapor. Hence, the key difference between steam and vapor is that steam is the gaseous state of water whereas vapor is the gaseous state of any substance. Moreover, steam is typically invisible while the vapor of some substances is colorful.

IRISSAK [1]3 years ago

5 0

Answer:

Hello There!!

Explanation:

Yes,they are different.

The difference between steam and water vapor is that water vapor is typically the same temperature as the air that is present while steam is above the boiling point of water. Vapour and steam are both gaseous states of matter.

hope this helps,have a great day!!

~Pinky~

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Calculate the specific heat in calories per °C of a 2.00 lb pure iron bar. Plz help me!!!

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Answer:

402.7897

Explanation:

Pretty sure but not 100% about it.

grams in 2 pounds = 907.184 * specific heat of iron = .444

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2 years ago

What is the amount of heat released by 1.00 gram of liquid water at 0°C when it changes to 1.00 gram of ice at 0°C?

QveST [7]

Answer:

334J/g

Explanation:

Data obtained from the question include:

Mass (m) = 1g

Specific heat of Fusion (Hf) = 334 J/g

Heat (Q) =?

Using the equation Q = m·Hf, we can obtain the heat released as follow:

Q = m·Hf

Q = 1 x 334

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Therefore, the amount of heat released is 334J

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3 years ago

What is the pH of a solution with a H+ ion of 2×10-¹²?

kap26 [50]

Answer:

11.7

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3 years ago

What is the mass of a sample of metal that is heated from 58.8°C to 88.9°C with a

Vadim26 [7]

Answer:

$\boxed {\boxed {\sf 333 \ grams}}$

Explanation:

We are asked to find the mass of a sample of metal. We are given temperatures, specific heat, and joules of heat, so we will use the following formula.

$Q= mc \Delta T$

The heat added is 4500.0 Joules. The mass of the sample is unknown. The specific heat is 0.4494 Joules per gram degree Celsius. The difference in temperature is found by subtracting the initial temperature from the final temperature.

ΔT= final temperature - initial temperature

The sample was heated from 58.8 degrees Celsius to 88.9 degrees Celsius.

ΔT= 88.9 °C - 58.8 °C = 30.1 °C

Now we know three variables:

Q= 4500.0 J
c= 0.4494 J/g°C
ΔT = 30.1 °C

Substitute these values into the formula.

$4500.0 \ J = m (0.4494 \ J/g \textdegree C)(30.1 \textdegree C)$

Multiply on the right side of the equation. The units of degrees Celsius cancel.

$4500.0 \ J = m (13.52694 J/g)$

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 13.52694 Joules per gram. The inverse operation of multiplication is division, so we divide both sides by 13.52694 J/g

$\frac {4500.0 \ J }{13.52694 J/g}= \frac{m (13.52694 J/g)}{13.52694 J/g}$

The units of Joules cancel.

$\frac {4500.0 \ J }{13.52694 J/g}= m$

$332.6694729 \ g =m$

The original measurements have 5,4, and 3 significant figures. Our answer must have the least number or 3. For the number we found, that is the ones place. The 6 in the tenth place tells us to round the 2 up to a 3.

$333 \ g \approx m$

The mass of the sample of metal is approximately 333 grams.

8 0

2 years ago