Question

Doubling which quantity would cause the largest increase in a spring’s elastic potential energy?

Answer 1

on edge it is DISPLACEMENT

Answer 2

Answer:

potential energy is maximum when streach distance of string is doubled

Explanation:

we know that elastic potential energy of a spring is given as

$E_{p}=\frac{1}{2}kx^2$..................(1)

here k is spring constant

and x is stretched distance of spring

if we double the spring constant then potential energy will be given as

$E_{1}=\frac{1}{2}\times 2kx^2$

$E_{1}=kx^2$...............(2)

similarly if we double the stretch distance then potential energy in spring will be given as

$E_{2}=\frac{1}{2}\times 4kx^2$

$E_{2}=2kx^2$.............(3)

from equation 2 and equation 3 it is clear that

$E_{2}>E_{1}$

it means potential energy is maximum when stretch distance of string is doubled