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Contact [7]
2 years ago
6

How is the surface area of an average person is 2m^2 in the chapter pressure

Physics
2 answers:
iren [92.7K]2 years ago
6 0

Answer:

The total atmospheric pressure experienced by the person's whole body is, P = 202650 N/m²

Explanation:

Given data,

The surface area of the person, A = 2 m²

The standard atmospheric pressure is  P = 101325 N/m² (or), Pascal

This is the amount of pressure experienced by 1 m² body at sea level.

If the surface area of the person is, A = 2 m², then the pressure becomes,

                                  P = 2 x 101325 N/m²

                                    = 202650 N/m²

Hence the total atmospheric pressure experienced by the person's whole body is, P = 202650 N/m²

11Alexandr11 [23.1K]2 years ago
3 0

Answer:

We have to show surface area =2m^2,with few conditions that is by considering Force =200000\ N and Pressure =100000\ Pa to be respectively.

Explanation:

The atmospheric pressure is =10^{5}\ Pa on Earth's surface.

The magnitude of the force exerted on a person by the atmosphere is =2\times 10^{5}\N (or)\ 200kN\ (or)\ 20\ ton.

Now to calculate surface area we can find it from pressure=\frac{force}{area} and re-arranging it to.

area=\frac{force}{pressure}

So plugging the values,

Surface area =\frac{20000}{10000}=2\ m^{2}

Hence from the above calculations we can say that surface area is 2m^2.

So the surface area of an average person can be said to have 2m^2, using the concept of pressure and force.

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A 129-kg horizontal platform is a uniform disk of radius 1.61 m and can rotate about the vertical axis through its center. A 65.
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Answer:

Moment of inertia of the system is 289.088 kg.m^2

Explanation:

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⇒ I_y_y=I_d_i_s_k + I_m_a_n+I_d_o_g

⇒ I_y_y=\frac{M_d_i_s_k(R_d_i_s_k)^2}{2} +M_m(r_c)^2+M_d_o_g(R_c)^2

⇒ I_y_y=\frac{129(1.61)^2}{2} +65.7(1.07)^2+27.2(1.31)^2

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192 = 48 x 2 x 3.14 x r

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