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horrorfan [7]
3 years ago
11

Consider a hypothetical reaction in which A and B are reactants, and C and D are products. If 26 grams of A completely reacts wi

th 12 grams of B to produce 14 grams of C, how many grams of D will be produced.
Chemistry
1 answer:
natali 33 [55]3 years ago
4 0

Answer:

The answer to your question is: 24 grams of D

Explanation:

To answer this question we need to remember the Lavoisier law of conservation of mass, which says that in a chemical reaction matter is neither created nor destroyed.

This means that the amount of matter stays the same.

Then, the reaction is

                    A      +      B      ⇒       C      +      D

                 26 g         12 g             14 g            x

mass                              

of reactants      38 g                              ?          mass of products, but it must be

                                                                          equal to the mass of products

Then                14g + x = 38

                        x = 38 - 14

                        x = 24 g of D                                                        

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An ideal gas in a cylindrical container of radius r and height h is kept at constant pressure p. The bottom of the container is
Juli2301 [7.4K]

Answer:

m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}  

Explanation:

The gas ideal law is  

PV= nRT (equation 1)

Where:

P = pressure  

R = gas constant  

T = temperature  

n= moles of substance  

V = volume  

Working with equation 1 we can get  

n =\frac{PV}{RT}

The number of moles is mass (m) / molecular weight (mw). Replacing this value in the equation we get.

\frac{m}{mw} =\frac{PV}{RT}  or  

m =\frac{P*V*mw}{R*T}   (equation 2)

The cylindrical container has a constant pressure p  

The volume is the volume of a cylinder this is

V =(pi)*r^{2}*h

Where:

r = radius  

h = height  

(pi) = number pi (3.1415)

This cylinder has a radius, r and height, h so the volume is  V =(pi)*r^{2}*h

Since the temperatures has linear distribution, we can say that the temperature in the cylinder is the average between the temperature in the top and in the bottom of the cylinder. This is:  

T =\frac{T_{1} + T_{O}}{2}  

Replacing these values in the equation 2 we get:

m =\frac{P*V*mw}{R*T}   (equation 2)

m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}    

8 0
4 years ago
What must group 16 do to become stable
tamaranim1 [39]
Group 16 must gain 2 electrons to become stable as stated in my other answer 

Hope this helped

7 0
3 years ago
Read 2 more answers
How many grams are in 2.3 x10-4 moles of calcium phosphate ca3(po3)2
Airida [17]

Answer:

calcium phosphate has the formula Ca3(PO4)2, which has the mass of 310 grams/mol.

1 mol contains 310 grams

2.3*10^-4 moles contain  2.3*10^-4 * 310, which means 713*10^-4 grams, or 71.3 milligrams.

If you wrote the formula right and named the compound wrong, all you have to do is replace 310 with 278 and the answer will be 639.4*10^-4 grams, or 63.94 milligrams.

6 0
3 years ago
CH4 is the ___________________ formula for methane.
Llana [10]
CH4 is the molecular formula for methane.
5 0
3 years ago
A gas has a volume of 6.6 L at a temperature of 40 C. What is the volume of
zaharov [31]

Answer:

6.07 L

Explanation:

It appears that the reading has been made at constant pressure .

At constant pressure , the gas law formula is

V/T = constant  V is volume and T is temperature of the gas.

V₁ / T₁ = V₂ / T₂

V₁ = 6.6 L ,

T₁ = 40°C

= 273 + 40

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T₂ = 15+ 273

= 288K

V₂ = ?

Putting the values in the formula above

6.6 / 313  = V₂ / 288

V₂ = 6.07 L.

8 0
4 years ago
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