I neeeed helpp please

Consider the voltaic cellZn(s) + Cu{2+}(aq)--> Zn{2+}(aq)+Cu(s){}=chargeUnder standard conditions, what is the maximum electr

blondinia [14]

Answer:

Max. work done in 60 g of copper plated out is 200472.14 J

Explanation:

Given cell reaction is:

$Zn(s)+Cu^{2+} \rightarrow Zn^{2+}+Cu(s)$

Standard reduction potential of Zn electrode ( $E_{Zn^{2+}/Zn}$ ) is 0.763 V.

Standard reduction potential of Cu electrode ( $E_{Cu^{2+}/Cu}$ ) is -0.337 V.

Copper acts as cathode and Zinc acts as anode.

Cell potential (E) = E° cathode - E° anode

= 0.763 - (-0.337)

= 1.10 V

formula for the work done is as follows:

$W_{max}=-nFE$

Here, n is no. of electron involved in the reaction.

F(Faraday's constant) = 96500

In the given reaction, n = 2

$W_{max}=-nFE\\=-2 \times\ 96500 \times 1.10\\=-212300\ J/mol$

Therefore, 212300 J work is done by reducting 1 mol of copper.

Copper given is 60 g.

Molecular mass of copper is 63.54 g/mol.

$No.\ of\ mol = \frac{60\ g}{63.54\ g/mol}$

Max. work done in 60 g of copper plated out is:

$W_{max}=212300\ J/mol \times \frac{60\ g}{63.54\ g/mol} \\=200472.14\ J$

3 0

3 years ago

1. A student has a petri dish packed with a layer of marbles. Which of the following activities should the student perform to de

Sindrei [870]

Answer: A.) Removing a few marbles from the petri dish and stirring the rest around as energy is added

B) The high temperature makes the gas molecules spread apart according to Charles's law because this law describes how a gas will behave at constant pressure.

Explanation: The phase transition from solid to liquid involves the use of energy to make the molecules present in solid to break the inter molecular forces and to start moving away from each other as in liquid. The molecules in solid are closely packed whereas in liquids they are loosely packed. Thus less number of molecules are present per unit volume in a liquid. Thus the marbles have to be removed to show less density and the energy has to supplied. Removing all but two marbles from the petri dish and shaking them vigorously as energy is added will give us a more disorderd state called gas in which the molecules are very far apart and the density is least.

B) According to Boyle's law the pressure is inversely proportional to the volume of the gas at constant temperature and constant number of moles. $P\propto \frac{1}{V}$ (At constant temperature and number of moles)

According to Charle's law the volume is directly proportional to the temperature of the gas at constant pressure and constant number of moles.

$V\propto T$ (At constant pressure and number of moles)

Thus as temperature of the gas increases , the volume also increases, and the density decreases. the gas becomes lighter and thus rises up.

7 0

3 years ago

Animals breathe oxygen and release carbon dioxide during cellular respiration according to the equation below. How much oxygen i

kifflom [539]

Answer:

14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.

Explanation:

Animals take in oxygen and breathe out carbon dioxide during cellular respiration. The reaction for the metabolism of the food in the animal body is:

$C_6H_{12}O_6 + O_2 \rightarrow 6CO_2 + 6H_2O + Energy$

As can be seen from the reaction stoichiometry that:

<u>6 moles of carbon dioxide gas can be produced from 1 mole of oxygen gas in the process of metabolism of glucose.</u>

Also,

Given :

Mass of carbon dioxide gas = 120 g

Molar mass of carbon dioxide gas = 44 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus, moles of carbon dioxide are:

$moles_{CO_2} = \frac{120 g}{44 g/mol}$

$moles_{CO_2} = 2.7273 mol$

As mentioned:

<u>6 moles of carbon dioxide</u> gas can be produced from <u>1 mole of oxygen gas</u> in the process of metabolism of glucose.

<u>1 mole of carbon dioxide</u> gas can be produced from <u>1/6 mole of oxygen gas</u> in the process of metabolism of glucose.

<u>2.7273 mole of carbon dioxide</u> gas can be produced from <u> $\frac{1}{6} \times 2.7273$ moles of oxygen gas</u> in the process of metabolism of glucose.

Thus, moles of oxygen gas needed = 0.4545 moles

Molar mass of oxygen gas = 32 g/mol

The mass of oxygen gas can be find out by using mole formula as:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Mass\ of\ oxygen\ gas = Moles \times Molar mass}$

$Mass\ of\ oxygen\ gas = 0.4545 \times 32}$

$Mass\ of\ oxygen\ gas = 14.544 g$

<u>14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.</u>

3 0

3 years ago

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HELP! ASAP!

harina [27]

Given the model from the question,

The products are: N₂, H₂O and H₂
The reactants are: H₂ and NO
The limiting reactant is H₂
The balanced equation is: 3H₂ + 2NO —> N₂ + 2H₂O + H₂

<h3>Balanced equation </h3>

From the model given, we obtained the ffolowing

Red => Oxygen
Blue => Nitrogen
White => Hydrogen

Thus, we can write the balanced equation as follow:

3H₂ + 2NO —> N₂ + 2H₂O + H₂

From the balanced equation above,

Reactants: H₂ and NO
Product: N₂, H₂O and H₂

<h3>How to determine the limiting reactant</h3>

3H₂ + 2NO —> N₂ + 2H₂O + H₂

From the balanced equation above,

3 moles of H₂ reacted with 2 moles of NO.

Therefore,

5 moles of H₂ will react with = (5 × 2) / 3 = 3.33 moles of NO

From the calculation made above, we can see that only 3.33 moles of NO out of 4 moles given are required to react completely with 5 moles of H₂.

Thus, H₂ is the limiting reactant

Learn more about stoichiometry:

brainly.com/question/14735801

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8 0

2 years ago

A scientist wants to perform a controlled experiment to test the effect of rust on chemically treated iron. which action would b

olga2289 [7]

The answer is to test a piece of untreated and treated under same conditions!

9 0

3 years ago

Read 2 more answers