Simply mulitply the volume by the density. As we shall see, this is dimensionally consistent.
Explanation:
density
ρ
=
Mass
Volume
, and thus units of
g
⋅
m
L
−
1
are reasonable.
For this problem:
17.4
⋅
m
L
×
0.798
⋅
g
⋅
m
L
−
1
≅
14
⋅
g
but A i supposed?
Answer:
Explanation:
There are some mistakes in writing the equation. However, Please check the below one and contact me again if necessary.
2KI(aq) + Pb(NO₃)₂ (aq) -> PbI₂ (s) + 2KNO₃
Answer:
The answer to your question is letter B
Explanation:
A.) 2 AgCl + Na2S ⟶ 2 Ag2S + 2 NaCl
Reactants Elements Products
2 Ag 4
2 Cl 2
2 Na 2
1 S 2
This reaction is unbalanced
B.) 2 AgCl + Na2S ⟶ Ag2S + 2 NaCl
Reactants Elements Products
2 Ag 2
2 Cl 2
2 Na 2
1 S 1
This reaction is balanced
C.) AgCl + Na2S ⟶ 2 Ag2S + 2 NaCl
Reactants Elements Products
1 Ag 4
1 Cl 2
2 Na 2
1 S 2
This reaction is unbalanced
D.) 2 AgCl + 2 Na2S ⟶ Ag2S + NaCl
Reactants Elements Products
2 Ag 4
2 Cl 1
4 Na 1
2 S 1
This reaction is unbalanced
Answer:
<u>Specific heat capacity</u> is the amount of heat required to change the temperature of 1 gram of a substance by 1 degree Celsius
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
The substances with higher value of specific heat capacity require more heat to raise the temperature by one degree as compared the substances having low value of specific heat capacity.For example,
The specific heat capacity of oil is 1.57 j/g. K and for water is 4.18 j/g.K. So, water take a time to increase its temperature by one degree by absorbing more heat while oil will heat up faster by absorbing less amount of heat.
Consider that both oil and water have same mass of 5g and change in temperature is 15 K. Thus amount of heat thy absorbed to raise the temperature is,
For oil:
Q = m.c. ΔT
Q = 5 g× 1.67 j/g K × 15 K
Q = 125.25 j
For water:
Q = m.c. ΔT
Q = 5 g× 4.18 j/g K × 15 K
Q = 313.5 j
we can observe that water require more heat which is 313.5 j to increase its temperature.
