A substance that is impenetrable by x-rays is described as being radiopaque.
Radiopaque substances will not allow x-rays and or other forms of radiations to pass through them.
Instead, they absorb or block the rays and when used in radiology, they appear white or light gray on photographic films.
Radiopaque materials are applied in generating ultrasound images and other forms of clinical procedures.
More on radiopaque materials can be found here: brainly.com/question/10583205?referrer=searchResults
Ammonia isn't an element, it's a compound made by mixing the elements Nitrogen and Hydrogen in the Haber process. Therefore, it isn't on the periodic table
Answer:
The standard cell potential of the reaction is 0.78 Volts.
Explanation:
![Cu^{2+}(aq)+Fe(s)\rightarrow Cu(s)+Fe^{2+}(aq)](https://tex.z-dn.net/?f=Cu%5E%7B2%2B%7D%28aq%29%2BFe%28s%29%5Crightarrow%20Cu%28s%29%2BFe%5E%7B2%2B%7D%28aq%29)
Reduction at cathode :
Reduction potential of
to Cu=![E^o_{1}=0.34 V](https://tex.z-dn.net/?f=E%5Eo_%7B1%7D%3D0.34%20V)
Oxidation at anode:
![Fe(s)\rightarrow Fe^{2+}(aq)+2e^-](https://tex.z-dn.net/?f=Fe%28s%29%5Crightarrow%20Fe%5E%7B2%2B%7D%28aq%29%2B2e%5E-)
Reduction potential of
to Fe=![E^o_{2}=-0.44 V](https://tex.z-dn.net/?f=E%5Eo_%7B2%7D%3D-0.44%20V)
To calculate the
of the reaction, we use the equation:
![E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}](https://tex.z-dn.net/?f=E%5Eo_%7Bcell%7D%3DE%5Eo_%7Bred%2Ccathode%7D-E%5Eo_%7Bred%2Canode%7D)
Putting values in above equation, we get:
![E^o_{cell}=0.34V -(-0.44 V)=0.78 V](https://tex.z-dn.net/?f=E%5Eo_%7Bcell%7D%3D0.34V%20-%28-0.44%20V%29%3D0.78%20V)
The standard cell potential of the reaction is 0.78 Volts.
Answer:B
Explanation:
The early theory says that atom Is the smallest indivisible particle. Which was later proven to contain electron neutron and proton
Answer:
Explanation:
50 * 10^100 is 50 googols in scientific notation... but
come on, who would write that in standard form...