Western regions Facts

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This region has both the state with the smallest population (Wyoming) and the largest population (California).
Alaska's land area is much bigger than any other state, but it has one of the lowest populations.
The western US takes up about half of the land of the United States.

The western United States is the region comprising the westernmost states of the United States. As American settlement in the U.S. expanded westward, the meaning of the term the West changed. Before about 1800, the crest of the Appalachian Mountains was seen as the western frontier.

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At 650 K, the reaction MgCO3(s)⇌MgO(s)+CO2(g)MgCO3(s)⇌MgO(s)+CO2(g) has Kp=0.026Kp=0.026. A 10.0-L container at 650 K has 1.0 g

Ray Of Light [21]

Answer:

0.4076 g

Explanation:

Kp is the equilibrium constant based on pressure and depends only on gas substances. For a generic reaction

aA + bB ⇄ cC + dD

$Kp = \frac{(pC)^c*(pD)^d}{(pA)^a*(pB)^b}$ , where pX is the pressure of X in equilibrium.

For the reaction Kp = pCO₂

pCO₂ = 0.026 atm

The system is in equilibrium at the beginning. The compression occurs at a constant temperature, so using Boyle's law

P1V1 = P2V2

0.026*10 = P2*0.1

P2 = 2.6 atm

The reaction will reach again the equilibrium, and pCO₂ = 0.026 atm, then the rest will form MgCO₃, which will be 2.6 - 0.026 = 2.574 atm.

By the ideal gas law:

PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.082 atm*L/mol*K), and T is the temperature.

2.574*0.1 = n*0.082*650

53.3n = 0.2574

n = 4.83x10⁻³ mol

The stoichiometry of the reaction is 1 mol of MgCO₃ for 1 mol of CO₂, so it will form 4.83x10⁻³ mol of MgCO₃ .

The molar mass is:

MgCO₃: 24 g/mol of Mg + 12 g/mol of C + 3*16 g/mol of O = 84 g/mol

The mass formed is the molar mass multiplied by the number of moles:

m = 84x4.83x10⁻³

m = 0.4076 g

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Write the balanced equation and solve the stoichiometry problem: The number of moles and mass of copper(II) carbonate needed to

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The number of moles and the mass (in kg) of copper(II) carbonate needed to decompose in order to produce 1.500 kg of copper(II) oxide, where CO2 is the other product.