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bearhunter [10]
3 years ago
7

A jogger runs at a speed of 3 m/s. How far does he run in 120 seconds?​

Physics
1 answer:
Licemer1 [7]3 years ago
8 0

Answer: *360 mph*

Explanation:

I am pretty sure that it is 360 mph

3 times 120 = 360

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Answer:

u = 10.63 m/s

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Explanation:

For Take-off speed ..

by using the standard range equation we have

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solving for u

u² = \frac{Rg}{sin2\theta}

u^2 = \frac{9.1 x 9.80}{sin26}

u^2 = 113.17

u = 10.63 m/s

for Max height

using the standard h(max) equation ..

v^2 = (v_osin\theta)^2 -2gh

h =\frac{(v_o^2sin\theta)^2}{2g}

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h = 1.10 m

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3 years ago
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8 0
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It should be A and C

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