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3 years ago

8

What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 1

0 24 kg and radius of the earth is 6.4 × 10 6 m.)

1 answer:

Free_Kalibri [48]3 years ago

7 0

Answer:

Explanation:

just use the gravational force equation which is G x m of earth x m of object divided by r squared (which is radius of earth)

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An asteroid is discovered in a nearly circular orbit around the Sun, with an orbital radius that is 3.570 times Earth's. What is

inysia [295]

Explanation:

Given:

$r_a = 3.570R_E$

$R_E = 1.499×10^{11}\:\text{m}$

$M_S = 1.989×10^{30}\:\text{kg}$

$G = 6.674×10^{-11}\:\text{N-m}^2\text{/kg}^2$

Let $m_s$ = mass of the asteroid and $r_a$ = orbital radius of the asteroid around the sun. The centripetal force $F_c$ is equal to the gravitational force $F_G:$

$F_c = F_G \Rightarrow m_a\dfrac{v_a^2}{r_a} = G\dfrac{m_aM_S}{r_a^2}$

or

$\dfrac{4\pi^2 r_a}{T^2} = G\dfrac{M_S}{r_a^2}$

where

$v = \dfrac{2\pi r_a}{T}$

with T = period of orbit. Rearranging the variables, we get

$T^2 = \dfrac{4\pi^2 r_a^3}{GM_S}$

Taking the square root,

$T = 2\pi \sqrt{\dfrac{r_a^3}{GM_S}}$

$\:\:\:\:=2\pi \sqrt{\dfrac{(3.57(1.499×10^{11}\:\text{m}))^3}{(6.674×10^{-11}\:\text{N-m}^2\text{/kg}^2)(1.989×10^{30}\:\text{kg})}}$

$\:\:\:\:= 2.13×10^8\:\text{s} = 6.75\:\text{years}$

3 0

3 years ago

assuming that the seafloor is spreading at a rate of 1.3cm/yr, calculate how long it took africa's west coast to move 2400 kn aw

Verdich [7]

Answer: 184,615,384.6 years

Explanation:

This problem can be solve by the following equation:

$V=\frac{d}{t}$ (1)

Where:

$V=1.3 \frac{cm}{year} \frac{1 km}{100000 cm}=0.000013 \frac{km}{year}$ is the spreading rate of the seafloor, its velocity

$d=2400 km$ is the distance the Africa's west coast moved at this rate

$t$ is the time it took to the coast to move the descibed distance

Isolating $t$ from (1):

$t=\frac{d}{V}$ (2)

$t=\frac{2400 km}{0.000013 \frac{km}{year}}$ (3)

Finally:

$t=184,615,384.6 years$ This is the time it took to the Africa's west coastto move away from the Mid atlantic ridge.

3 0

2 years ago

ou are to drive to an interview in another town, at a distance of 300 km on an expressway. The interview is at 11:15 a.m. You pl

Shkiper50 [21]

Answer:

133.62 kmh.

Explanation:

Time provided = 3.25 hours.

Distance to be covered 300 km

Times spent in first 100 km = 1 hour

Time spent in next 43 km

= 43 / 40 = 1.075 hours

Total time spent = 2.075 hours

Total distance covered = 143 km

Distance remaining = 300 - 143

=157 km .

Time remaining = 3.25 - 2.075

= 1.175

Speed required = Distance remaining / time remaining

= 157 / 1.175

= 133.62 kmh.

8 0

3 years ago

A negative slope on the velocity vs. time graph indicates that the object is not accelerating

liubo4ka [24]

AnswerNo

However, the acceleration is the opposite of the movement:

Explanation:

8 0

3 years ago

The density of air is 1.3 kg/m^3. What mass of air is contained in a room measuring 2.5m x 4m x 10m? Give your answer in kg. Bra

krek1111 [17]

Mass= density x volume
1.3 kg/m^3 x ( 2.5x4x10) m^3
= 130 kg

7 0

3 years ago