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horsena [70]
2 years ago
5

Which of the following statements cannot be supported by Kepler's laws of planetary motion?

Physics
1 answer:
Firdavs [7]2 years ago
7 0
The second
option is the answer
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Describe one practical use of a concave mirror.
Tatiana [17]

Answer:

Here are some uses...

Explanation:

Uses of convex mirror:

It is used in supermarkets and stores for surveillance.

It it is used as rear view mirror in automobiles.this is due to the reason that a convex mirror provides a wider field of view than a plane or concave mirror.

Uses of concave mirror:

It is used in torches.

They are used in headlights of vehicles to send parallel rays to infinity , in shaving mirror to get an enlarged image of the face and also by dentists to see a bigger image of the tooth / teeth .

Mark as brainliest if helped thanks!

7 0
3 years ago
Read 2 more answers
Two pebbles are dropped into a pool of water as shown. If a new wave with a
Kazeer [188]

Answer:

Constructive interference

Explanation:

3 0
3 years ago
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A listener increases his distance from a sound source by a factor of 4.49.
noname [10]

Answer: Δβ (dB) = -13.1dB

Explanation:

The intensity of sound is inversely proportional to the square of the distance between them.

I ∝ 1/r²

I₁/I₂= r₂²/r₁² .....1

When the listener increases his distance from the source by a factor of 4.49.

Then,

r₂/r₁= 4.49

From equation 1

I₁/I₂ = (4.49)²

I₁/I₂ = 20.16

I₂/I₁ = 1/20.16

The change in sound intensity in dB can be given as

Δβ (dB) = 10 log(I₂/l₁) = 10log(1/20.6) = -13.1dB

6 0
3 years ago
Use the equation of motion to answer the question. Use the equation of motion to answer the question.
satela [25.4K]

The final position of the object after 2 s is 11 m.

Motion: This can be defined as the change in position of a body.

⇒ Formula:

  • x = x₀+v₀t+1/2(at²)........................ Equation 1

⇒ Where:

  • x = Final position of the object
  • x₀ = Starting position
  • v₀ = Starting velocity
  • t = time
  • a = acceleration

From the question,

⇒ Given:

  • x₀ = 4.5 m/s
  • t = 2 s
  • x₀ = 2m
  • a = 0 m/s²

⇒ Substitute these values into equation 1

  • x = 2+(4.5×2)+1/2(0²×2)
  • x = 2+9+0
  • x = 11 m

Hence, The final position of the object after 2 s is 11 m

Learn more about motion here: brainly.com/question/15531840

4 0
2 years ago
A speed bike tops a hill at 3.50 m/s and accelerates steadily down the hill until reaching a speed of 11.4 m/s after 4.20 second
k0ka [10]

Answer:

The bike traveled 31.3 meters during this period

Explanation:

A speed bike tops a hill at 3.50 m/s and accelerates steadily down the

hill until reaching a speed of 11.4 m/s after 4.20 seconds

→ The initial speed u = 3.5 m/s

→ The final speed v = 11.4 m/s

→ The time of acceleration t = 4.2 seconds

→ a = \frac{v-u}{t}

Substitute the values above in the rule to find the acceleration a

→ a = \frac{11.4-3.5}{4.2} = 1.88 m/s²

We need to find the distance that the bike traveled during the

acceleration

→ v² = u² + 2 a s, where s is the distance

→ (11.4)² = (3.5)² + 2 (1.88)(s)

→ 129.96 = 12.25 + 3.76 s

Subtract 12.25 from both sides

→ 117.71 = 3.76 s

Divide both sides by 3.76

→ s = 31.3 meters

<em>The bike traveled 31.3 meters during this period</em>

8 0
3 years ago
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