Which molecule is an aromatic hydrocarbon?

Which factors play a role in creating ocean waves

amm1812

The moon plays a huge factor in creating ocean waves

3 0

4 years ago

Read 2 more answers

What mass of silver chloride can be produced from 1.65 l of a 0.240 m solution of silver nitrate?

Liono4ka [1.6K]

Check table T and use the concentration equation. Molarity= moles of solute/ liters of solution.

So 0.240 = x/ 1.65 once u find the # of miles of solute (x=.396) and substitute that

Wait I'm not sure if it's correct

4 0

4 years ago

A mixture of 0.220 moles CO, 0.350 moles H2 and 0.640 moles He has a total

emmasim [6.3K]

Answer:

P(H₂) = 0.8533 atm

Explanation:

n(CO) = 0.220 mole

n(H₂) = 0.350 mole

n(He) = 0.640 mole

_______________

∑ n = 1.210 moles

mole fraction => X(H₂) = 0.350/1.210 = 0.2892

Dalton's Law of Partial Pressures => P(H₂) = X(H₂)·P(ttl) = 0.2892(2.95 atm) = 0.8533 atm

6 0

3 years ago

a calorimeter contained 75.0 g of water at 16.95 C. A 93.3-g sample of iron at 65.58 C was placed in it, giving a final temperat

Nostrana [21]

Answer:- $\frac{382.69J}{0C}$ .

Solution:- Mass of Iron added to water is 93.3 g. Initial temperature of iron metal is 65.58 degree C and final temperature of the system is 19.68 degree C.

temperature change, $\Delta T$ for iron metal = 65.58 - 19.68 = 45.9 degree C

specific heat for the metal is given as 0.444 J per g per degree C.

let's calculate the heat lost by iron metal using the equation:

$q=mc\Delta T$

where, q is the heat energy, m is mass, c is specific heat and delta T is change in temperature. let's plug in the values and calculate q for iron metal:

$q=93.3g(45.9^0C)(\frac{0.444J}{g.^0C})$