A mass M is suspended from a spring and oscillates with a period of 0.940 s. Each complete oscillation results in an amplitude r
1 answer:
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Answer:
the only effect it has is to create more induced charge at the closest points, but the net face remains zero, so it has no effect on the flow.
Explanation:
We can answer this exercise using Gauss's law
Ф = ∫ e . dA = / ε₀
field flow is directly proportionate to the charge found inside it, therefore if we place a Gaussian surface outside the plastic spherical shell. the flow must be zero since the charge of the sphere is equal induced in the shell, for which the net charge is zero. we see with this analysis that this shell meets the requirement to block the elective field
From the same Gaussian law it follows that if the sphere is not in the center, the only effect it has is to create more induced charge at the closest points, but the net face remains zero, so it has no effect on the flow , so no matter where the sphere is, the total induced charge is always equal to the charge on the sphere.
Answer:
Time taken = 10400 s
Explanation:
Given:
Initial speed of the train,
Final speed of the train,
Displacement of the train,
Using Newton's equation of motion,
Now, using Newton's equation of motion for displacement,
Now, plug in the value of in the above equation. This gives,
Now, plug in 234000 m for , 25 m/s for
and 20 m/s for
. Solve for
.
Therefore, the time taken by the train is 10400 s.
Answer:
(a) 0.3778 eV
(b) Ratio = 0.0278
Explanation:
The Bohr's formula for the calculation of the energy of the electron in nth orbit is:
(a) The energy of the electron in n= 6 excited state is:
Ionisation energy is the amount of this energy required to remove the electron. Thus, |E| = 0.3778 eV
(b) For first orbit energy is:
Ratio = 0.0278