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lesantik [10]
3 years ago
9

A 4.2 kg sled is being pulled along a snow-covered road with a rope that exerts a horizontal force of 6.0 n and, at that moment,

is accelerating at 1.1 m/s2 on level ground with friction having no significant effect. what is the normal force on the sled?
Physics
2 answers:
Pavlova-9 [17]3 years ago
8 0
Normal force is equal to the formula of mg where m is the gravitational acceleration and g is the mass of the object. This is only applicable when the force is acting in the direction of the gravitational field and the  object is placed horizontally.So the formula is normal force = mg since the problem depicts what the statement is talking about.
So NF = mg= 9.8 m/s^2* 4.2kg= 41.16 N or 41 N
Stella [2.4K]3 years ago
6 0
<span>the body is moving horizontally, it doesnt matter watever kind of horizontal forces are acting.
 Therefore the normal force is equal to the weight
 N=mg=4.2*9.8=41N
 Note: the other data in the problem have no relevance
 answer
</span> the normal force on the sled is 41N 
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The mass of calcium phosphate the reaction can produce is <u>6.076</u> grams.

<h3>What is mass?</h3>

Mass is a numerical measure of inertia, which is a basic feature of all matter. It is, in effect, a body of matter's resistance to a change in speed or position caused by the application of a force.

In the International System of Units (SI), the kilogram is the unit of mass.

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The spring is released and a 0.10-kilogram plastic sphere is fired from the launcher. Calculate the maximum speed with which the
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Answer:

A) The elastic potential energy stored in the spring when it is compressed 0.10 m is 0.25 J.

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Explanation:

Hi there!

I´ve found the complete problem on the web:

<em>A toy launcher that is used to launch small plastic spheres horizontally contains a spring with a spring constant of 50. newtons per meter. The spring is compressed a distance of 0.10 meter when the launcher is ready to launch a plastic sphere.</em>

<em>A) Determine the elastic potential energy stored in the spring when the launcher is ready to launch a plastic sphere.</em>

<em>B) The spring is released and a 0.10-kilogram plastic sphere is fired from the launcher. Calculate the maximum speed with which the plastic sphere will be launched. [Neglect friction.] [Show all work, including the equation and substitution with units.]</em>

<em />

A) The elastic potential energy (EPE) is calculated as follows:

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Where:

k = spring constant.

x = compressing distance

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The elastic potential energy stored in the spring when it is compressed 0.10 m is 0.25 J.

B) Since there is no friction, all the stored potential energy will be converted into kinetic energy when the spring is released. The equation of kinetic energy (KE) is the following:

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v = velocity

The kinetic energy of the sphere will be equal to the initial elastic potential energy:

KE = EPE = 1/2 · m · v²

0.25 J = 1/2 · 0.10 kg · v²

2 · 0.25 J / 0.10 kg = v²

v = 2.2 m/s

The maximum speed of the plastic sphere will be 2.2 m/s

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