1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lesantik [10]
4 years ago
9

A 4.2 kg sled is being pulled along a snow-covered road with a rope that exerts a horizontal force of 6.0 n and, at that moment,

is accelerating at 1.1 m/s2 on level ground with friction having no significant effect. what is the normal force on the sled?
Physics
2 answers:
Pavlova-9 [17]4 years ago
8 0
Normal force is equal to the formula of mg where m is the gravitational acceleration and g is the mass of the object. This is only applicable when the force is acting in the direction of the gravitational field and the  object is placed horizontally.So the formula is normal force = mg since the problem depicts what the statement is talking about.
So NF = mg= 9.8 m/s^2* 4.2kg= 41.16 N or 41 N
Stella [2.4K]4 years ago
6 0
<span>the body is moving horizontally, it doesnt matter watever kind of horizontal forces are acting.
 Therefore the normal force is equal to the weight
 N=mg=4.2*9.8=41N
 Note: the other data in the problem have no relevance
 answer
</span> the normal force on the sled is 41N 
You might be interested in
A photon of wavelength 2.78 pm scatters at an angle of 147° from an initially stationary, unbound electron. What is the de Brogl
Elena-2011 [213]

Answer:

2.07 pm

Explanation:

The problem given here is the very well known Compton effect which is expressed as

\lambda^{'}-\lambda=\frac{h}{m_e c}(1-cos\theta)

here, \lambda is the initial photon wavelength, \lambda^{'} is the scattered photon wavelength, h is he Planck's constant, m_e is the free electron mass, c is the velocity of light, \theta is the angle of scattering.

Given that, the scattering angle is, \theta=147^{\circ}

Putting the respective values, we get

\lambda^{'}-\lambda=\frac{6.626\times 10^{-34} }{9.11\times 10^{-31}\times 3\times 10^{8} } (1-cos147^\circ ) m\\\lambda^{'}-\lambda=2.42\times 10^{-12} (1-cos147^\circ ) m.\\\lambda^{'}-\lambda=2.42(1-cos147^\circ ) p.m.\\\lambda^{'}-\lambda=4.45 p.m.

Here, the photon's incident wavelength is \lamda=2.78pm

Therefore,

\lambda^{'}=2.78+4.45=7.23 pm

From the conservation of momentum,

\vec{P_\lambda}=\vec{P_{\lambda^{'}}}+\vec{P_e}

where,\vec{P_\lambda} is the initial photon momentum, \vec{P_{\lambda^{'}}} is the final photon momentum and \vec{P_e} is the scattered electron momentum.

Expanding the vector sum, we get

P^2_{e}=P^2_{\lambda}+P^2_{\lambda^{'}}-2P_\lambda P_{\lambda^{'}}cos\theta

Now expressing the momentum in terms of De-Broglie wavelength

P=h/\lambda,

and putting it in the above equation we get,

\lambda_{e}=\frac{\lambda \lambda^{'}}{\sqrt{\lambda^{2}+\lambda^{2}_{'}-2\lambda \lambda^{'} cos\theta}}

Therefore,

\lambda_{e}=\frac{2.78\times 7.23}{\sqrt{2.78^{2}+7.23^{2}-2\times 2.78\times 7.23\times cos147^\circ }} pm\\\lambda_{e}=\frac{20.0994}{9.68} = 2.07 pm

This is the de Broglie wavelength of the electron after scattering.

6 0
4 years ago
Key concepts <br><br> (Example | scientific method
nekit [7.7K]
Vocabulary should be, I think: 
I. Hypothesis 
II. Evidence, data
III. Experiment

What is your question exactly? 

3 0
3 years ago
Read 2 more answers
A wave has a velocity of 24 m/s and a period of 3.0 s. Calculate the wavelength of the wave.
Katyanochek1 [597]

Velocity (unit:m/s) of the wave is given with the formula:

v=f∧,

where f is the frequency which tells us how many waves are passing a point per second (unit: Hz) and ∧ is the wavelength, which tells us the length of those waves in metres (unit:m)

f=1/T , where T is the period of the wave.

In our case: f=1/3

∧=v/f=24m/s/1/3=24*3=72m

5 0
3 years ago
A trip is taken that passes through the following points in order
riadik2000 [5.3K]

Answer:

35, I got you bro, i got you

8 0
3 years ago
Not sure if it went through last time. Please help asap!
Olin [163]
The equation for force is F=ma. Because we have the value of mass (0.42 kg) and the acceleration (14.8 m/s^2), simply plug them into the equation for force to get
0.42 \times 14.8 = 6.22
The answer is 6.22 N because newtons are the unit used to measure force.
8 0
3 years ago
Read 2 more answers
Other questions:
  • This part of the electromagnet spectrum produces heat and with special equipment can locate people at night.
    14·2 answers
  • Which kind of force do you exert on an object when you pull it toward you?
    11·2 answers
  • In an atom, electrons ____.
    15·2 answers
  • The sound wave produced can best be described as a ?
    12·1 answer
  • A dentist’s drill starts from rest. After 1.46 sof constant angular acceleration, it turns at arate of 27000 rev/min.Find the dr
    9·1 answer
  • An empty parallel plate capacitor is connected between the terminals of a 9.0-V battery and charged up. The capacitor is then di
    6·1 answer
  • What are four pieces of evidence for continental drift?
    7·2 answers
  • Car 1 drives 20 mph to the south, and car 2 drives 30 mph to the north. From
    10·1 answer
  • HELP PLS and HURRY
    14·1 answer
  • Find the rate constantrif the population doubles in 12 days.b.ifp= 200 initially (whent= 0), what is the population whent= 18 da
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!