The homogeneous, reversible, exothermic, liquid phase reaction: A근R Is being carried out in a reactor system consisting of an id
eal PFR followed by an ideal CSTR. The volume of the PFR is 75,000 L, and the volume of the CSTR is 150,000 L. The PFR operates at 150 °C, and the CSTR operates at 125 °C. The volumetric flow rate entering the PFR is 55,000 L/h, the concentration of A in this stream is 6.5 M, and the concentration of R is zero. The reaction is first order in both directions. The rate constant of the forward reaction at 150 °C is 1.28 h and the equilibrium constant based on concertation at 150 °C is 2.5. The rate constant at 125 °C is 0.280 h and the equilibrium constant is 3.51. (a) What is the rate of R leaving the CSTR (mol/h)? (b) The flowrate to the PFR is increased so that the fractional conversion of A is 0.5 in the efluent from the CSTR. All other parameters remain unchanged. What is the new production rate of R?
1 answer:
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Answer:
A) 5 MPa , 55 MPa
B) maximum stress = 55 MPa, maximum shear stress = 25 MPa
Explanation:
using the given Data
free surface of a solid body
α = 50 MPa, α
= 10 MPa , t
= -15 MPa
attached below is the detailed solution to the question
True
(I’m not sure if that’s right a picture below may help with the answer too)
(I’m not sure if that’s right a picture below may help with the answer too)
Answer:
A.) 1mv = 2000N
B.) Impulse = 60Ns
C.) Acceleration = 66.67 m/s^2
Velocity = 4 m/s
Displacement = 0.075 metre
Absorbed energy = 60 J
Explanation:
A.) Using a mathematical linear equation,
Y = MX + C
Where M = (2000 - 0)/( 898 - 0 )
M = 2000/898
M = 2.23
Let Y = 2000 and X = 898
2000 = 2.23(898) + C
2000 = 2000 + C
C = 0
We can therefore conclude that
1 mV = 2000N
B.) Impulse is the product of force and time.
Also, impulse = momentum
Given that
Mass M = 30kg
Velocity V = 2 m/s
Impulse = M × V = momentum
Impulse = 30 × 2 = 60 Ns
C.) Force = mass × acceleration
F = ma
Substitute force and mass into the formula
2000 = 30a
Make a the subject of formula
a = 2000/30
acceleration a = 66.67 m/s^2
Since impulse = 60 Ns
From Newton 2nd law,
Force = rate of change in momentum
Where
change in momentum = -MV - (- MU)
Impulse = -MV + MU
Where U = initial velocity
60 = -60 + MU
30U = 120
U = 120/30
U = 4 m/s
Force = 2000N
Impulse = Ft
Substitute force and impulse to get time
60 = 2000t
t = 60/2000
t = 0.03 second
Using third equation of motion
V^2 = U^2 + 2as
Where S = displacement
4^2 = 2^2 + 2 × 66.67S
16 = 4 + 133.4S
133.4S = 10
S = 10/133.4
S = 0.075 metre
D.) Energy = 1/2 mV^2
Energy = 0.5 × 30 × 2^2
Energy = 15 × 4 = 60J
