Before turning in a test, it would be best to
2 answers:
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Answer:
hello your question is incomplete attached below is the complete question
A) optimum compressor ratio = 9.144
B) specific thrust = 2.155 N.s /kg
C) Thrust specific fuel consumption = 1670.4 kg/N.h
Explanation:
Given data :
Mo = 2.1 , To = 220k , Tt4 = 1700 k, hpr = 42000 kj/kg, Cp = 1.004 kj/ kg.k
γ = 1.4
attached below is the detailed solution
Answer:
volume of biological sludge = 28.566 m³ per day
Explanation:
given data
mass of solid = 7240 kg/day
initial moisture content = 78%
solution
here percentage of solid will be
% of solid = 100 - initial moisture content
% of solid = 100 - 78 = 22 %
so that
mass of sludge produced = kg per day
put her value
mass of sludge produced = kg
mass of sludge produced = 32909.09 kg
so
specific gravity of sludge =
and as we know that
= 1.152
so that
density of sludge = S sludge × density of water
density of sludge = 1.152 × 1000
density of sludge = 1152 kg/m³
so that
volume of biological sludge =
volume of biological sludge =
volume of biological sludge = 28.566 m³ per day