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tatiyna
3 years ago
13

The diagram below represents the rock cycle.

Physics
2 answers:
Rasek [7]3 years ago
8 0

<em>Answer:</em>

<em>It is C.Heat and pressure .......................</em>

<em>Just............. </em>

<em>                       Need.............</em>

<em>                                                              20............</em>

<em></em>

<em></em>

<em>                                                                                                      Charaters.............</em>

<em></em>

lara31 [8.8K]3 years ago
5 0

Answer:

C. Heat and Pressure

Explanation:

The arrow which is labeled A points from igneous rock to metamorphic rock.

There are three types of Rocks:

1. Igneous Rock

2. Metamorphic Rock

3. Sedimentary Rock

Rock cycle:

Rock cycle is the process that describes the transition between these three types of rocks. Each type has its own form and its own equilibrium condition. The rock type alters when it is pushed out of its equilibrium conditions.

Transition of Igneous rock to Metamorphic rock:

Igneous rock forms when magma cools down. The transition of Igneous Rock to Metamorphic Rock is a result of a process called Metamorphism. Metamorphism is the alteration in the structure of rock as a result of certain heat and pressure conditions. Inside Earth heat comes from pressure. Heat with pressure does not melt the rock but it bakes the rock. Baking is not melting but it changes the shape of the rock while it is still solid. It actually forms crystals. Because the rock changes its structure, it is called Metamorphic Rock.

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3 years ago
A pyrotechnical releases a 3 kg firecracker from rest. at t=0.4 s, the firecracker is moving downward with a speed 4 m/s. At the
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Explanation:

This exercise is a case at the moment, let's define the system formed by the firecracker and its two parts, in this case the forces during the explosion are internal and the moment is conserved

Initial, before the explosion

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     v = -4.0 m / s

Final after division

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a) before the explosion the only force acting on the body is gravity

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     F = 3 10 = 30 N

b) The expression for momentum is

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Before the explosion the only force that acts is the weight

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    v₂f = (M v - m₁ v₁f) / m₂

    v₂f = (3 (-4) - 1 6) / 2

   v₂f = - 9 m / 2

The negative sign indicates that body 2 (botton) is descending

Now we can use the momentum and momentum relationship for the body during the explosion

    I = F t = Dp

   F t = pf –po)

   F t= [m₁ v₁f + m₂ v₂f]

   

   I = [1 6 + 2 (-9) -0]

   I = -12 N s

This is the impulse during the explosion the negative sign indicates that it is headed down

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I₀ = Mv

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I₀ =-12 N s

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ΔI = - 12 – (-12)

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3 0
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Answer:

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Learn more about a protostar here:

brainly.com/question/12534975

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