<span>The acrylic plastic rod is 200 mm long and 15 mm in
diameter. If an axial load of 300 N is applied to it, determine
the change in its length and the change in its diameter.
. latd = -0.0002515 (15) = -0.00377 mm
elat = -Velong = -0.4(0.0006288) = -0.0002515
d = elong L = 0.0006288 (200) = 0.126 mm
elong = s
E = 1.697(106
)
2.70(109
) = 0.0006288
s = P
A = 300 p
4 (0.015)2 = 1.697 MPa
•3–25. T</span>
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Explanation:
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