(a) 138.2 J
Since the applied force is parallel to the displacement of the block, the work done by the force is given by:
where
F = 46.7 N is the magnitude of the force
d = 2.96 m is the displacement of the block
Substituting the numbers into the equation, we find
(b) 45.1 J
In order to calculate the total energy dissipated among the floor and the block as thermal energy, we have to calculate the work done by the frictional force, which is
where
is the coefficient of friction
m = 4.35 kg is the mass of the block
g = 9.8 m/s^2
d = 2.96 m is the displacement
and the negative sign is due to the fact that the frictional force has opposite direction to the displacement.
Substituting, we find
The magnitude of this work is equal to the sum of the thermal energy dissipated between the floor and the block:
And since we know
we find
(c) 58.1 J
According to the work-energy theorem, the increase in kinetic energy of the block must be equal to the work done by the applied force minus the work done by friction (which becomes wasted thermal energy):
Substituting
We find
Answer:
Explanation:
<em>Position is the location of the object (whether it's a person, a ball, or a particle) at a given moment in time.</em>
<em>Displacement is the difference in the object's position from one time to another.</em>
<em>Distance is the total amount the object has traveled in a certain period of time.</em>
<em />
<em>I hope this helps!</em>
<em />
Answer:
Fc = 1579 [N]; ac = 15790.9 [m/s^2]
Explanation:
To solve this problem we must use the following formula that relates the centripetal force to the speed of rotation and the radius of rotation, respectively.
a)
where:
Fc = centripetal force [N]
m = mass [kg]
v = tangential velocity [m/s]
r = radius [m]
We have to give a mass to the stone in order to solve the problem, for this case we will say that the mass is equal to 100 [g].
The tangential velocity is equal to the product of the angular velocity (rotational) by the turning radius
v = w * r
But we need to convert the angular velocity units of revolutions per second to radians per second
v = 25.13*25 = 628.31[m/s]
Now replacing in the first equation:
![F_{c}=0.1*\frac{628.31^{2} }{25} \\F_{c}= 1579 [N]](https://tex.z-dn.net/?f=F_%7Bc%7D%3D0.1%2A%5Cfrac%7B628.31%5E%7B2%7D%20%7D%7B25%7D%20%5C%5CF_%7Bc%7D%3D%201579%20%5BN%5D)
b)
The second part will be only:
![a_{c}=\frac{v^{2} }{r} \\a_{c}=\frac{628.31^{2} }{25} \\a_{c}=15790.93[m/s^{2} ]](https://tex.z-dn.net/?f=a_%7Bc%7D%3D%5Cfrac%7Bv%5E%7B2%7D%20%7D%7Br%7D%20%5C%5Ca_%7Bc%7D%3D%5Cfrac%7B628.31%5E%7B2%7D%20%7D%7B25%7D%20%5C%5Ca_%7Bc%7D%3D15790.93%5Bm%2Fs%5E%7B2%7D%20%5D)
Answer:
That the speed of light is constant
Explanation:
E = mc2
This question is math why u put it on chemistry tho
