Answer:
The period of rotation is
T=8.025s
Explanation:
The person is undergoing simple harmonic motion on the wheel
Given data
mass of the person =75kg
Radius of wheel r=16m
Velocity =8.25m/s
The oscillating period of simple harmonic motion is given as
T=(2*pi)/2=2*pi √r/g
Assuming that g=9.81m/s
Substituting our data into the expression we have
T=2*3.142 √ 16/9.81
T=6.284*1.277
T=8.025s
Answer:
The weight lifter would not get past this sticking point.
Explanation:
Generally torque applied on the weight is mathematically represented as
T = F z
To obtain Elbow torque we substitute 4000 N for F (the force ) and 2cm for z the perpendicular distance
So Elbow Torque is
To obtain the torque required we substitute 300 N for F and 30cm
So the Required Torque is
Now since it mean that the weight lifter would not get past this sticking point
Answer:
Explanation:
Given that,
The instantaneous current in the circuit is giveen by :
We need to find the rms value of the current.
The general equation of current is given by :
It means,
We know that,
So, the rms value of current is 2.12 A.