The net force on the cylinder depends on several independent variables such as mass, acceleration, velocity, time, etc, and it is given as F(net) = ma.
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Net force exerted on the cylinder</h3>
The net force on the cylinder is calculated from Newton's second law of motion.
F(net) = ma
F(net) = m(v/t)
where;
- m is mass of the cylinder
- a is acceleration of the cylinder
- v is velocity of the cylinder
- t is time of motion of the cylinder
Thus, the net force on the cylinder depends on several independent variables such as mass, acceleration, velocity, time, etc, and it is given as F(net) = ma.
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Answer:
9.96x10^-20 kg-m/s
Explanation:
Momentum p is the product of mass and velocity, i.e
P = mv
Alpha particles, like helium nuclei, have a net spin of zero. Due to the mechanism of their production in standard alpha radioactive decay, alpha particles generally have a kinetic energy of about 5 MeV, and a velocity in the vicinity of 5% the speed of light.
From this we calculate the speed as
v = 5% 0f 3x10^8 m/s (speed of light)
v = 1.5x10^7 m/s
The mass of an alpha particle is approximately 6.64×10−27 kg
Therefore,
P = 1.5x10^7 x 6.64×10^−27
P = 9.96x10^-20 kg-m/s
Answer:
As given that the car maintains a constant speed v as it traverses the hill and valley where both the valley and hill have a radius of curvature R.
(i) At point C, the normal force acting on the car is largest because the centripetal force is up. gravity is down and normal force is up. net force is up so magnitude of normal force must be greater than the car's weight.
(ii) At point A, the normal force acting on the car is smallest because the centripetal force is down. gravity is down and normal force is up. net force is up so magnitude of normal force must be less than car's weight.
(iii) At point C, the driver will feel heaviest because the driver's apparent weight is the normal force on her body.
(iv) At point A, the driver will feel the lightest.
(v)The car can go that much fast without losing contact with the road at A can be determined as follow:
Fn=0 - lose contact with road
Fg= mv²/r
mg=mv²/r
v=sqrt (gr)
Answer:
Explanation:
To find Depth D of lake we must need to find the time taken to hit the water.So we use equation of simple motion as:
Δx=vit+(1/2)at²
As we have find the time taken now we need to find the final velocity vf from below equation as
So the depth of lake is given by:
first we need to find total time as
t=3.0-1.01 =1.99 s
