Answer
given,
x = (3.9 cm)sin[(9.3 rad/s)πt]
general equation of displacement
x = A sin ω t
A is amplitude
now on comparing
c) Amplitude =3.9 cm
a) frequency =
f = 4.65 Hz
b) period of motion
T = 0.215 s
d) time when displacement is equal to x= 2.6 cm
x = (3.9 cm)sin[(9.3 rad/s)πt]
2.6 = (3.9 cm)sin[(9.3 rad/s)πt]
sin[(9.3 rad/s)πt] = 0.667
9.3 π t = 0.73
t = 0.025 s
Answer:
The amount of force applied to his body is 1944.44 N
<em>The chances of the person dying is very high owing to the high impact force with which the person would experience when he or she lands on the asphalt road due to the jump out of the moving car.</em>
Explanation:
We all know that,
F = Ma where,
F = Force
M = weight of the person
a = acceleration or velocity of the moving car
Therefore;
F = { 70 x (100 x 1000) } / [3600]
= [7 000 000] / 3600
= <u>1944.44 N</u>
F = 500N
S = 5m
T = 1.2s
----------------------------------
P = ?
We can use formula P = F * V, just because it was a smooth slide we can assume that average speed was V = S/T = 5 / 1.2 = 50/12
So the final answer would be:
P = F * V = 500 * 50/12
Are you sure those are correct numbers? The answer don't look nice :D
Answer:
Fc = 1.7x10^-4 N
Explanation:
Convert everything to proper units:
m = 25mg = 2.5x10^-5 kg
r = 17.6cm = 0.176m
v = 110cm/s = 1.1m/s
the formula for centripetal force is Fc = mv^2 / r
Plug everything and solve for Fc;
fc = (2.5x10^-5)(1.1^2) / 0.176
Fc = 1.7x10^-4 N
