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3 years ago

One of the best ways to avoid injury while riding a bike

Physics

2 answers:

mel-nik [20]3 years ago

5 0

know how to ride a bike simply put also wear safety gear like a helmet knee pads things like that

hope this helps

Klio2033 [76]3 years ago

3 0

The absolute best, foolproof, reliable way is to not fall off or run into anything.

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Which structure is part of the inner ear?

ValentinkaMS [17]

cochlea is part of the inner ear. have a great day my friend

8 0

3 years ago

Read 2 more answers

MODERN PHYSICS

frosja888 [35]

Answer:

D. n=6 to n=2

Explanation:

Given;

energy of emitted photon, E = 3.02 electron volts

The energy levels of a Hydrogen atom is given as; E = -E₀ /n²

where;

E₀ is the energy level of an electron in ground state = -13.6 eV

n is the energy level

From the equation above make n, the subject of the formula;

n² = -E₀ / E

n² = 13.6 eV / 3.02 eV

n² = 4.5

n = √4.5

n = 2

When electron moves from higher energy level to a lower energy level it emits photons;

$E = E_0(\frac{1}{n_1^2}-\frac{1}{n_2^2} )\\\\\frac{1}{n_1^2}-\frac{1}{n_2^2} = \frac{E}{E_o} \\\\\frac{1}{4} -\frac{1}{n_2^2} = \frac{3.02}{13.6} \\\\\frac{1}{4} -\frac{1}{n_2^2} =0.222\\\\\frac{1}{n_2^2} = 0.25 - 0.22\\\\\frac{1}{n_2^2} = 0.03\\\\n_2^2 = 33.33\\\\n_2 = \sqrt{33.33} = 6$

For a photon to be emitted, electron must move from higher energy level to a lower energy level. The higher energy level is 6 while the lower energy level is 2

Therefore, The electron energy-level transition is from n = 6 to n = 2

3 0

3 years ago

A car is driving towards an intersection when the light turns red. The brakes apply a constant force of 1,398 newtons to bring t

dmitriy555 [2]

Answer:

the initial velocity of the car is 12.04 m/s

Explanation:

Given;

force applied by the break, f = 1,398 N

distance moved by the car before stopping, d = 25 m

weight of the car, W = 4,729 N

The mass of the car is calculated as;

W = mg

m = W/g

m = (4,729) / (9.81)

m = 482.06 kg

The deceleration of the car when the force was applied;

-F = ma

a = -F/m

a = -1,398 / 482.06

a = -2.9 m/s²

The initial velocity of the car is calculated as;

v² = u² + 2ad

where;

v is the final velocity of the car at the point it stops = 0

u is the initial velocity of the car before the break was applied

0 = u² + 2(-a)d

0 = u² - 2ad

u² = 2ad

u = √2ad

u = √(2 x 2.9 x 25)

u =√(145)

u = 12.04 m/s

Therefore, the initial velocity of the car is 12.04 m/s

7 0

3 years ago

A car's gas tank contains 58.7 kg

Bogdan [553]

Answer:

721 kg/m^3

Explanation:

Trust me bro

8 0

3 years ago

A magnetic field directed along the x-axis changes with time according to B (0.06t2+2.25) T, where t is in seconds. The field is

Gemiola [76]

Answer:

$E = 2 \times 10^{-3} V$

Explanation:

As we know that rate of change in flux will induce EMF

So here we can

$EMF = \frac{d\phi}{dt}$

now we have

$EMF = \pi r^2\frac{dB}{dt}$

now we also know that induced EMF is given by

$\int E. dL = \pi r^2\frac{dB}[dt}$

$E (2\pi r) = \pi r^2\frac{dB}{dt}$

$E = \frac{r}{2}(\frac{dB}{dt})$

now plug in all values in it

$E = \frac{0.0133}{2}(0.12 t)$

$E = 8 \times 10^{-4} (2.50) = 2 \times 10^{-3} V/m$

5 0

4 years ago