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harkovskaia [24]
3 years ago
9

How many moles of silver (Ag) are present in a sample of 3.8 × 1024 atoms Ag?

Chemistry
2 answers:
const2013 [10]3 years ago
4 0

Answer : The correct option is, (C) 6.3 mole Ag

Explanation : Given,

Number of atoms of Ag = 3.8\times 10^{24}

As we know that, 1 mole contains 6.022\times 10^{23} number of atoms.

As, 6.022\times 10^{23} number Ag atoms present in 1 mole of Ag

So, 3.8\times 10^{24} number Ag atoms present in \frac{3.8\times 10^{24}}{6.022\times 10^{23}}=6.3 mole of Ag

Therefore, the number of moles of Ag present are, 6.3 moles

xz_007 [3.2K]3 years ago
3 0

1 mol=6.022 x 10²³ atoms.

1 mol-----------------------------6.022 * 10²³ atoms
   x--------------------------------3.8 * 10²⁴ atoms

x=(1 mol * 3.8 * 10²⁴ atoms) / 6.022*10²³ atoms=6.3 moles of Ag,

Answer: C. 6.3 mol Ag
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4 0
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