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Nookie1986 [14]
3 years ago
15

Select the Newman projection that corresponds to the following molecule 2. Select the choice that best describes the relationshi

p of the following pair of compounds

Chemistry
2 answers:
OverLord2011 [107]3 years ago
4 0
The relationship of a pair of compounds could be one between these options : 
- Structural isomerisms
happened when molecules with same molecular formula have bonded together in different orders
- Stereoisomerism
Happened when two or more compounds differing only in the spatial arrangement of their atom

hope this helps
Setler [38]3 years ago
4 0

Both compounds have cis-trans geometry isomers

Both carbon compounds have a double bond and both carbon atoms bind two different groups

<h3>Further explanation </h3>

Isomers are two compounds that have the same chemical formula but different structural formulas

There is a grouping of isomers in Hydrocarbons:

  • 1. Isomer structure consists of skeletal isomers, position isomers, and function isomers
  • 2. Stereoisomers consist of geometric isomers and optical isomers

Geometric isomers occur because of differences in the direction of the groups in the molecule

geometrical isomers are found in compounds that have double bonds such as alkenes and the two atoms bind 2 different groups, so that if the location of the groups is exchanged the shape becomes different

If a similar group is located on the same side of the double bond it is called -cis, but if the group is opposite it is called -trans

Example:

Atomicity to 2 butenes. Where in cis-2 butene, both methyl groups are located on the same side whereas, in trans-2 butene, both methyl groups are opposite

The difference in the structure of the two compounds results in differences in physical properties such as the boiling point

The greater the number of carbon atoms making up it, the more the number of isomers

<h3>Learn more </h3>

'cis' and trans'

brainly.com/question/5644969#

an organic compound contains the following functional group

brainly.com/question/2288180

6-decene is not possible

brainly.com/question/2095052

Keywords: geometric isomer, cis-trans

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balandron [24]
To answer the questions,

(1) Activation energy is the amount of energy that is needed for the reaction to proceed, converting the reactant to products. The answer is letter B.

(2) The rate of chemical reaction normally increases as the reactant concentration is increased. The answer is letter C. 

6 0
3 years ago
Read 2 more answers
A gas sample occupies 5.38L at 36.0C. what is its temperature if volume is changed to 4.86L
Alina [70]

Answer: 2.5°C

Explanation:

Initial volume V1 = 5.38 liters

Initial temperature T1 = 36.0°C

Convert temperature in Celsius to Kelvin

(32°C + 273= 305K)

Final temperature T2 = ?

Final volume V2 = 4.68 liters

According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

Thus, Charles' Law is expressed as: V1/T1 = V2/T2

5.38/305 = 4.86/T2

To get the value of T2, cross multiply

5.38 x T2 = 4.86 x 305

5.38T2 = 1482.3

Divide both sides by 5.38

5.38T2/5.38 = 1482.3/5.38

T2 = 275.5K

Convert 275.5K to Celsius

(275.5K - 273K = 2.5°C)

Thus, the final temperature is 2.5°C

6 0
3 years ago
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8 0
4 years ago
Enthalpy of formation (kJ/mol) C6H12O6(s)-1260 O2 (g)0 CO2 (g)-393.5 H2O (l)-285.8 Calculate the enthalpy of combustion per mole
trapecia [35]

Answer : The enthalpy of combustion per mole of C_6H_{12}O_6 is -2815.8 kJ/mol

Explanation :

Enthalpy change : It is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H^o

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]

The equilibrium reaction follows:

C_6H_{12}O_6(s)+6O_2(g)\rightleftharpoons 6CO_2(g)+6H_2O(l)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(n_{(CO_2)}\times \Delta H^o_f_{(CO_2)})+(n_{(H_2O)}\times \Delta H^o_f_{(H_2O)})]-[(n_{(C_6H_{12}O_6)}\times \Delta H^o_f_{(C_6H_{12}O_6)})+(n_{(O_2)}\times \Delta H^o_f_{(O_2)})]

We are given:

\Delta H^o_f_{(C_6H_{12}O_6(s))}=-1260kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_f_{(H_2O(l))}=-285.8kJ/mol

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(6\times -393.5)+(6\times -285.8)]-[(1\times -1260)+(6\times 0)]=-2815.8kJ/mol

Therefore, the enthalpy of combustion per mole of C_6H_{12}O_6 is -2815.8 kJ/mol

6 0
4 years ago
Read 2 more answers
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Charra [1.4K]
An acid is a substance that donates hydrogen ions. Because of this, when an acid is dissolved in water, the balance between hydrogen ions and hydroxide ions is shifted. Now there are more hydrogen ions than hydroxide ions in the solution. This kind of solution is acidic.
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3 years ago
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