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denis-greek [22]
4 years ago
9

What are the overall problems with hydrogen energy

Physics
1 answer:
OlgaM077 [116]4 years ago
7 0

Expensive: Hydrogen gas actually takes a considerable measure of work to free if from different components. If it were basic and simple to separate, everybody would be utilizing it. It’s now being utilized to power some hybrid vehicles, yet right now it is not a reasonable type of fuel for everybody, mainly because it’s pricey and it’s difficult to get it from place to place. Until research and innovation goes far enough to make this a simpler and cheaper task, hydrogen will likely be something that only the rich can afford.Not Enough Hydrogen Fuel Stations: As you likely know, it’s very difficult to change “the way things are.” As difficult as hydrogen is to create and transport, it gets to be considerably pricier when you consider attempting to utilize it to supplant fuel. There is no current framework set up to hydrogen as the primary fuel for the normal driver. Service stations and vehicles themselves would all must be changed in order to use hydrogen, which can take a lot of time and money to do. It doesn’t seem cost efficient to change from the norm.Safety Concerns: Hydrogen in itself has a lot of power behind it. Though it is less dangerous than gasoline, it’s profoundly flammable and constantly in the news for the potential dangers connected with it. Unlike gas, hydrogen has no smell. Sensors must be used to detect a leak.

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6. A car is traveling at 50m/s when it begins to slow down to
ki77a [65]

Answer:

-6 m/s²

Explanation:

Given:

v₀ = 50 m/s

v = 20 m/s

t = 5 s

Find: a

v = at + v₀

20 m/s = a (5 s) + 50 m/s

a = -6 m/s²

8 0
3 years ago
1. Una carga Q1 = + 12 μC se coloca a una distancia r = 0.024 m desde una carga Q2 = + 16 μC. a) Determina la magnitud de la fue
lyudmila [28]

Answer:

1. a. 3,000 N

b. Repulsión

2. 46.875 × 10⁶ N/C

3. a. 81,000 J

b. 6.75 × 10⁹ V

Explanation:

1. Los parámetros dados son;

Q₁ = +12 μC, Q₂ = +16 μC

La distancia entre las cargas, r = 0.024

La magnitud de la fuerza electrostática, F, entre cargas se da como sigue;

F = k \times \dfrac{Q_1 \cdot Q_2}{r^2}

Donde, k = constante de Coulomb = 9.0 × 10⁹ N · m² / C²

Por lo tanto, obtenemos;

F = 9.0 × 10⁹ × 12 × 10⁻⁶ × 16 × 10⁻⁶ / 0.024² = 3.000

La magnitud de la fuerza electrostática, entre las cargas, F = 3000 N

(b) Dado que tanto Q₁ como Q₂ son cargas positivas, y las cargas iguales se repelen entre sí, la fuerza es la repulsión.

2) La intensidad de un campo eléctrico, E, se da como sigue;

E = \dfrac{k \cdot Q}{r^2}

La magnitud de la carga, Q = 24 μC

La distancia donde se mide el campo, r = 48 mm = 0.048 m

Por lo tanto, E = 9.0 × 10⁹ × 12 × 10⁻⁶ / 0.048² = 46,875,000 N / C

La intensidad de un campo eléctrico, E = 46,875,000 N / C = 46.875 × 10⁶ N / C

3. La magnitud de las cargas son;

Q₁ = 24 mC

Q₂ = -12 μC

La distancia entre las cargas, r = 0.032 m

un. El potencial eléctrico de una carga, U_E , se da de la siguiente manera;

U_E = k \times \dfrac{Q_1 \cdot Q_2}{r}

Por lo tanto;

U_E = 9.0×10⁹ × 24 × 10⁻³ × (-12) × 10⁻⁶ /0.032 = -81,000

La energía potencial eléctrica entre la carga, Q₁ y Q₂= -81,000 J

b. El potencial eléctrico de Q₁ en Q₂, V₁ = k \times \dfrac{Q_1 }{r}

Por lo tanto, V₁ = 9.0×10⁹ × 24 × 10⁻³/0.032 = 6.75 × 10⁹

El potencial eléctrico de Q₁ en Q₂, V₁ = 6.75 × 10⁹ V

3 0
3 years ago
Two birds collide in midair. Before the collision their combined momentum was 35kg•m/sto the east. What is their combined moment
katrin [286]

Answer:

b

Explanation:

8 0
3 years ago
Read 2 more answers
A motorcycle of 170 kg is moving with a velocity 25m/ . Calculate the kinetic energy
topjm [15]

Answer: 53125joules

Explanation: The formula for kinetic energy is 1/2mv^2.

So we would have

1/2[(170)(25x25)]=53125

3 0
3 years ago
1-Autotrophic plants are also called
tresset_1 [31]

Answer:

1. Producers

2. cell (guards)

3. Rhizobium

4. Rafflesia Arnoldii

5. Xylem

3 0
3 years ago
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