Average speed = (total distance) / (time to cover the distance)
Total distance = (15 x 10m) = 150 m
Time to cover the distance = 60 s
Average speed = (150m) / (60s) = (150/60) m/s = 2.5 m/s
We have no way to describe the frog's velocity, because we have
no information about the direction of any this activity.
The sum of neutrons and protons defines the mass number of an isotope.
Answer: Option A
<u>Explanation:</u>
Isotopes of an element are defined as an element that possess the same number of protons but different number of neutrons in each atom. Hence the mass number in an isotope depends upon the two sub particles which are number of nucleons (i.e) the number of protons and neutrons. For example: carbon - 12 and carbon - 13 are examples of isotopes, the carbon element with mass number as 12 and 13.
At a temperature of 298 K, the Henry's law constant is 0.00130 M/atm for oxygen. The solubility of oxygen in water 1.00 atm would be calculated as follows:
<span>S = (H) (Pgas) = 0.00130 M / atm x 0.21 atm = 0.000273 M
</span>
At 0.890 atm,
<span>S = (H)(Pgas) = 0.00130 M / atm x 0.1869 atm = 0.00024297 M</span>
<span>
If atmospheric pressure would suddenly change from 1.00 atm to 0.890 atm at the same temperature, the amount of oxygen that will be released from 3.30 L of water in an unsealed container would be as follows</span>
<span>
3.30 L x (0.000273 mol / L) = 0.0012012 mol</span>
3.30 L x (0.00024297 mol / L) = 0.001069068 mol
0.0012012 mol - 0.001069068 mol = 0.000132 mol
In order for work to be done a force must be exerted on an object causing it to move
Answer:
Explanation:
Given that,
Mass of first car
M1= 328kg
The car is moving in positive direction of x axis with velocity
U1 = 19.1m/s
Velocity of second car
U2 = 13m/s, in the same direction as the first car..
Mass of second car
M2 = 790kg
Velocity of second car after collision
V2 = 15.1 m/s
Velocity of first car after collision
V1 =?
This is an elastic collision,
And using the conservation of momentum principle
Momentum before collision is equal to momentum after collision
P(before) = P(after)
M1•U1 + M2•U2 = M1•V1 + M2•V2
328 × 19.1 + 790 × 13 = 328 × V1 + 790 × 15.1
16534.8 = 328•V1 + 11929
328•V1 = 16534.8—11929
328•V1 = 4605.8
V1 = 4605.8/328
V1 = 14.04 m/s
The velocity of the first car after collision is 14.04 m/s
