Given Information:
Number of turns = N = 1130 turns
Length of solenoid = L = 0.430 m
Magnetic field = B = 1.0x10⁻⁴ T
Required Information:
Current = I = ?
Answer:
I = 0.0302 A
Explanation:
The current flowing in the solenoid winding can be found using
I = BL/μ₀N
Where μ₀ is the permeability of free space, N is the number of turns, B is the magnetic field and L is the length of solenoid
I = 1.0x10⁻⁴*0.430/4πx10⁻⁷
*1130
I = 0.0302 A
or
I = 30.28 mA
Answer:
I = 8.75 kg m
Explanation:
This is a rotational movement exercise, let's start with kinetic energy
K = ½ I w²
They tell us that K = 330 J, let's find the angular velocity with kinematics
w² = w₀² + 2 α θ
as part of rest w₀ = 0
w = √ 2α θ
let's reduce the revolutions to the SI system
θ = 30.0 rev (2π rad / 1 rev) = 60π rad
let's calculate the angular velocity
w = √(2 0.200 60π)
w = 8.683 rad / s
we clear from the first equation
I = 2K / w²
let's calculate
I = 2 330 / 8,683²
I = 8.75 kg m
The mass number of an isotope is the sum of the numbers of protons and the numbers of the neutron. Given that the mass number is 65 and the number of neutrons is 35, the number of protons is 30. The atom is then Zinc (Zn). The charge is equal to +2, as it lacks 2 more electrons.
