Answer:
Use the method on the image and solve it.
The Moon is 3.8 108 m from Earth and has a mass of 7.34 1022 kg. 5.97 1024 kg is the mass of the Earth.
<h3>What kind of gravitational pull does the moon have on the planet?</h3>
On the surface of the Moon, the acceleration caused by gravity around 1.625 m/s2 which is 16.6% greater than on the surface of the Earth 0.166.
<h3>What does the Earth's center's gravitational pull feel like?</h3>
Gravity is zero if you are in the centre of the earth since everything around you is pulling "up" (up is the only direction).
<h3>Where is the Earth's and the moon's gravitational centre?</h3>
It is around 1700 kilometres below Earth's surface.
To know more about gravitational force visit:-
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Answer:
Therefore, the moment of inertia is:
Explanation:
The period of an oscillation equation of a solid pendulum is given by:
(1)
Where:
- I is the moment of inertia
- M is the mass of the pendulum
- d is the distance from the center of mass to the pivot
- g is the gravity
Let's solve the equation (1) for I
![T=2\pi \sqrt{\frac{I}{Mgd}}](https://tex.z-dn.net/?f=T%3D2%5Cpi%20%5Csqrt%7B%5Cfrac%7BI%7D%7BMgd%7D%7D)
![I=Mgd(\frac{T}{2\pi})^{2}](https://tex.z-dn.net/?f=I%3DMgd%28%5Cfrac%7BT%7D%7B2%5Cpi%7D%29%5E%7B2%7D)
Before find I, we need to remember that
Now, the moment of inertia will be:
Therefore, the moment of inertia is:
I hope it helps you!
Answer:
0.02585 BTU
Explanation:
Given: Spring constant, k = 270 lbf/in
Initial force, f =100 lbf
Compression, x = 1 in
Work done can be calculated as follows:
![W = \int {(f+kx)} \, dx \\W = fx + \frac{1}{2}kx^2\\W= (100 lbf)(1 in)+ \frac{1}{2}(270 lbf/in)(1 in)^2\\W= 100+135 = 235 lbf in\\W=235 \times 0.00011 BTU = 0.02585 BTU](https://tex.z-dn.net/?f=W%20%3D%20%5Cint%20%7B%28f%2Bkx%29%7D%20%5C%2C%20dx%20%5C%5CW%20%3D%20fx%20%2B%20%5Cfrac%7B1%7D%7B2%7Dkx%5E2%5C%5CW%3D%20%28100%20lbf%29%281%20in%29%2B%20%5Cfrac%7B1%7D%7B2%7D%28270%20lbf%2Fin%29%281%20in%29%5E2%5C%5CW%3D%20100%2B135%20%3D%20235%20lbf%20in%5C%5CW%3D235%20%5Ctimes%200.00011%20BTU%20%3D%200.02585%20BTU)
Answer:
528 liter.
Explanation:
Volume of the tank(cuboid) = l*b*h
But volume of the water = l*b*h
Where
l= length of the tank
b = width of the tank
h = the length from the bottom of the tank,
3.55 in to m,
0.09017m
Length of the water in the tank = 0.570 - 0.09017
= 0.47983 m.
Volume = 0.47983*0.710*1.55
= 0.528 m3.
1 m3 = 1000 liter.
0.528 m3 = 0.528*1000
= 528 liter