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scoundrel [369]
2 years ago
5

Anyone know a GOOD show on Netflix please kid shows pleaseeeee

Physics
2 answers:
Afina-wow [57]2 years ago
7 0

Answer:

like horror? or action haha

Explanation:

raketka [301]2 years ago
4 0

Answer:

Avatar and last kids on earth ( your missing out on a lot of great shows the there when you get older watch Arcane.)

Explanation:

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What is power, and what is its relationship to voltage and amperage? (4 points)
tigry1 [53]

Answer:

The relationship between amperage, voltage, and power is that power equals the amperage quantity times the amount of voltage.

Explanation: brainliest pls

5 0
3 years ago
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Why does the sample on a microscope slide need to be very thin?
ziro4ka [17]

B. so light can shine through it from below.

4 0
3 years ago
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So, RCF, or relative centrifugal force should be equal to RCF = <img src="https://tex.z-dn.net/?f=11%2C18%2Ar%2A%28RPM%2F1000%29
zysi [14]

After plugging all the data into the equation, the result of the relative centrifugal force (RCF)  is measured in terms of g.

<h3>What is relative centrifugal force?</h3>

The relative centrifugal force (RCF) or the g force is the radial force generated by the spinning rotor as expressed relative to the earth's gravitational force.

RCF = ac/g

where;

  • ac is centripetal acceleration
  • g is acceleration due to gravity

RCF = \frac{\omega ^2 r}{g} = 1.118\times 10^{-5} \ (RPM)^2 r = 11.18r\ (RPM/1000)^2

where;

  • r is radius in cm

<h3>For example, </h3>

Find the maximum RCF of the JS-4.2 rotor can be obtained from its maximum speed (4200 rpm) and its rmax (250 mm);

RCF = 11.18 \times 25\ cm \times (\frac{4200 \ RPM}{1000} )^2 = 4,930.3 \times g

Thus, after plugging all the data into the equation, the result is measured in terms of g.

Learn more about relative centrifugal force here: brainly.com/question/26887699

#SPJ1

6 0
1 year ago
Covert 1000 kg/m3 into 1g/cm3
Lana71 [14]

Answer:

1 g/cm³

Explanation:

1 kg = 1000 g

1 cm = 0.01 of a meter

1 m³ = 100 cm * 100 cm * 100 cm = 1,000,000 cm

1,000 kg / 1 * 1000 g / 1 kg

^ divided by 1,000,000 cm

1,000,000 divided by 1,000,000 = 1 g/cm³

6 0
2 years ago
Two stationary positive point charges, charge 1 of magnitude 3.25 nC and charge 2 of magnitude 2.00 nC , are separated by a dist
Liula [17]

Complete Question

Two stationary positive point charges, charge 1 of magnitude 3.25 nC and charge 2 of magnitude 2.00 nC , are separated by a distance of 58.0 cm . An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges.

Required:

What is the speed of the electron when it is 10.0 cm from the +3.25-nC charge?

Answer:

The velocity is v = 80.82 \ m/s

Explanation:

From  the question we are told that

   The magnitude of charge one is  q_1 =  3.25 nC  =  3.25 *10^{-9} \  C

   The  magnitude of charge two  q_2  =  2.00 \ nC  =  2.00 *10^{-9} \ C

   The distance of separation is   d =  58.0 \ cm  =  0.58 \ m

 

Generally the electric potential of the electron at the midway point is mathematically represented as

         V  =  \frac{ q_1 }{\frac{d}{2} }  + \frac{ q_2}{\frac{d}{2} }

substituting values

         V  =  \frac{ 3.25 *10^{-9} }{\frac{ 0.58}{2} }  +  \frac{ 2 *10^{-9} }{\frac{ 0.58}{2} }

          V  =  1.8103 *10^{-8} \  V

Now when the electron is 10 cm   =  0.10 m  from charge 1 , it is  (0.58 - 0.10 =  0.48 m ) m from charge two

Now the electric potential  at that point is mathematically represented as

       V_1  =  \frac{q_1}{ 0.10}  +  \frac{q_2}{ 0.48}

 substituting values

      V_1  =  \frac{3.25 *10^{-9}}{ 0.10}  +  \frac{2.0*10^{-9}}{ 0.48}

      V_1  = 3.67*10^{-8}  \ V

Now the law of energy conservation ,

   The  kinetic energy of the electron  =  potential energy of the electron

i.e     \frac{1}{2} * m * v^2  =  [V_1 -  V]* q

where q is the magnitude of the charge on the electron with value

      q = 1.60  *10^{-19} \ C

While m is the mass of the electron with value  m = 9.11*10^{-31} \  kg

        \frac{1}{2} * 9.11 *10^{-19} * v^2  =  [ (3.67 -  1.8103) *10^{-8}]* 1.60 *10^{-19}

         v = \sqrt{6532.4}

        v = 80.82 \ m/s

 

4 0
3 years ago
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