Answer:
Explanation:
The given pH = 8.55
Unknown:
[H₃O⁺] = ?
[OH⁻] = ?
In order to find these unknowns we must first establish some relationship.
pH = -log[H₃O⁺]
8.55 = -log[H₃O⁺]
[H₃O⁺] = inverse log₁₀(-8.55) = 2.82 x 10⁻⁹moldm⁻³
To find the [OH⁻],
pH + pOH = 14
pOH = 14 - pH = 14 - 8.55
pOH = 5.45
pOH = -log[OH⁻]
[OH⁻] = inverse log₁₀ (-5.45) = 3.55 x 10⁻⁶moldm⁻³
The solution is basic because it has more concentration of OH⁻ ions compared to H⁺ ions.
It’s hydrosphere if it’s right lmk
For question 5 it is 3 two physical properties
Explanation:
meet .google .com/sxr-wgwg-vnc
Answer:
The concentration of fructose-6-phosphate is 1.50x10⁻³M
Explanation:
Gibbs Free energy, ΔG°, is defined as:
ΔG° = -RTln K
<em>Where ΔG° = 1670J/mol</em>
<em>R is gas constant = 8.314J/molK</em>
<em>T is absolute temperature (25°C + 273.15 = 298.15K)</em>
Thus, equilibrium constant, k, is:
1670J/mol = -8.314J/molK* 298.15K ln K
-0.6737 = ln K
0.5098 = K
K of the reaction:
G6P ⇄ F6P
is:
K = 0.5098 = [F6P] / [G6P]
As [G6P] is 2.95x10⁻³M:
0.5098 = [F6P] / [2.95x10⁻³M]
[F6P] = 1.50x10⁻³M
<h3>The concentration of fructose-6-phosphate is 1.50x10⁻³M</h3>