Answer:
A branch circuit is the circuit conductor between the final overcurrent device protecting the circuit and the outlet(s). Branch circuits are divided into four categories: appliance, general purpose, individual and multiwire
Explanation:
Answer:
<em>UP</em>
Explanation:
heat flows from higher level to lower level
( higher concentration to lower concentration )
and since temperature in above block is less than the lower block, the heat will flow from lower block to higher block .
( Up )
This is a physical change because cutting the string didn't change it chemically, but it did physically.
Water expands when it freezes (that's why you should never put closed, fully filled water bottles in the freezer !)
Let say the point is inside the cylinder
then as per Gauss' law we have
![\int E.dA = \frac{q}{\epcilon_0}](https://tex.z-dn.net/?f=%5Cint%20E.dA%20%3D%20%5Cfrac%7Bq%7D%7B%5Cepcilon_0%7D)
here q = charge inside the gaussian surface.
Now if our point is inside the cylinder then we can say that gaussian surface has charge less than total charge.
we will calculate the charge first which is given as
![q = \int \rho dV](https://tex.z-dn.net/?f=%20q%20%3D%20%5Cint%20%5Crho%20dV)
![q = \rho * \pi r^2 *L](https://tex.z-dn.net/?f=%20q%20%3D%20%5Crho%20%2A%20%5Cpi%20r%5E2%20%2AL)
now using the equation of Gauss law we will have
![\int E.dA = \frac{\rho * \pi r^2* L}{\epcilon_0}](https://tex.z-dn.net/?f=%5Cint%20E.dA%20%3D%20%5Cfrac%7B%5Crho%20%2A%20%5Cpi%20r%5E2%2A%20L%7D%7B%5Cepcilon_0%7D)
![E. 2\pi r L = \frac{\rho * \pi r^2* L}{\epcilon_0}](https://tex.z-dn.net/?f=E.%202%5Cpi%20r%20L%20%3D%20%5Cfrac%7B%5Crho%20%2A%20%5Cpi%20r%5E2%2A%20L%7D%7B%5Cepcilon_0%7D)
now we will have
![E = \frac{\rho r}{2 \epcilon_0}](https://tex.z-dn.net/?f=%20E%20%3D%20%5Cfrac%7B%5Crho%20r%7D%7B2%20%5Cepcilon_0%7D)
Now if we have a situation that the point lies outside the cylinder
we will calculate the charge first which is given as it is now the total charge of the cylinder
![q = \int \rho dV](https://tex.z-dn.net/?f=%20q%20%3D%20%5Cint%20%5Crho%20dV)
![q = \rho * \pi r_0^2 *L](https://tex.z-dn.net/?f=%20q%20%3D%20%5Crho%20%2A%20%5Cpi%20r_0%5E2%20%2AL)
now using the equation of Gauss law we will have
![\int E.dA = \frac{\rho * \pi r_0^2* L}{\epcilon_0}](https://tex.z-dn.net/?f=%5Cint%20E.dA%20%3D%20%5Cfrac%7B%5Crho%20%2A%20%5Cpi%20r_0%5E2%2A%20L%7D%7B%5Cepcilon_0%7D)
![E. 2\pi r L = \frac{\rho * \pi r_0^2* L}{\epcilon_0}](https://tex.z-dn.net/?f=E.%202%5Cpi%20r%20L%20%3D%20%5Cfrac%7B%5Crho%20%2A%20%5Cpi%20r_0%5E2%2A%20L%7D%7B%5Cepcilon_0%7D)
now we will have