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loris [4]
3 years ago
15

Let two objects of equal mass m collide. Object 1 has initial velocityv, directed to the right, and object 2 isinitially station

ary.
If the collision is perfectly elastic, whatare the final velocities v_1 and v_2 of objects 1 and 2?
Physics
1 answer:
3241004551 [841]3 years ago
8 0
<span>Our equation 1 would be
m*v=M*V1+m*V2
v=V1+V2
 v-V1=V2 

the equation 2 would look like this
 </span>V^2=V1^2+V2^2  
V^2-V1^2=V2^2
(V-V1)*(V+V1)=V2^2Dividing with the 1
V+V1=V2 
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A long uniform board weighs 52.8 N (10.6 lbs) rests on a support at its mid point. Two children weighing 206.0 N (41.2 lbs) and
natima [27]

The upward force exerted on the board by the support is 530.8 N.

<h3>Upward force exerted on the board by the support</h3>

The sum of the upward forces is equal to sum of downward forces;

total downward forces = 52.8 N + 206 N + 272 N = 530.8 N

downward force = upward force = 530.8 N

Thus, the upward force exerted on the board by the support is 530.8 N.

Learn more about upward force here: brainly.com/question/6080367

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1 year ago
Why electric forces are assential to forming compunds?
lidiya [134]
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8 0
3 years ago
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A wave traveling in water has a frequency of 500.0 Hz and a wavelength of 3.00 m. What is the speed of the wave?
Sergeu [11.5K]

Answer:

1500 m/s

Explanation:

Recall that for a wave,

Speed = frequency x wavelength

here we are given frequency = 500 Hz and wavelength = 3m

simply substitute into above equation

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6 0
3 years ago
A brick is resting on a smooth wooden board that is at a 30° angle. What is one way to overcome the static friction that is hold
nata0808 [166]

Answer:

We apply force to move the brick.

Explanation:

Let me first of define a force .

A force is something applied to an object or thing to change it's internal or external state.

Now if a brick is resting on smooth wood inclined at 30° to the horizontal for us to overcome the friction which is also a force we have to apply a force greater than the gravity force acting on the body and then depending on the direction of the applied force the angle to apply it also.

3 0
3 years ago
This is a two part question:
adelina 88 [10]

Answer:

1. 310 N

2. 310 N

Explanation:

1. Determination of the net force.

Force applied (Fₐ) = 430 N

Force experience (Fₑ) = 120 N

Net force (Fₙ) =?

Fₙ = Fₐ – Fₑ

Fₙ = 430 – 120

Fₙ = 310 N

Hence, the net force acting on the crate is 310 N

2. Determination of the net force.

Force applied (Fₐ) = 375 N

Force of friction (Fբ) = 65 N

Net force (Fₙ) =?

Fₙ = Fₐ – Fբ

Fₙ = 375 – 65

Fₙ = 310 N

Hence, the net force acting on the crate is 310 N.

8 0
2 years ago
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