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vfiekz [6]
3 years ago
13

Complete and balance the molecular equation, including phases, for the reaction of aqueous sodium sulfate, Na2SO4, and aqueous b

arium nitrate, Ba(NO3)2.
Chemistry
2 answers:
forsale [732]3 years ago
7 0
Na2SO4(aq)+Ba(NO3)2(aq)------------2NaNO3(aq)+BaSO4(s)
Montano1993 [528]3 years ago
5 0

<u>Answer:</u> The balanced molecular equation is written below.

<u>Explanation:</u>

A molecular equation is defined as the chemical equation in which the ionic compounds are written as molecules rather than component ions.

When sodium sulfate reacts with barium nitrate, it leads to the formation of white precipitate of barium sulfate and an aqueous solution of sodium nitrate.

The balanced chemical equation for the above reaction follows:

Na_2SO_4(aq.)+Ba(NO_3)_2(aq.)\rightarrow BaSO_4(s)+2NaNO_3(aq.)

By Stoichiometry of the reaction:

1 mole of aqueous solution of sodium sulfate reacts with 1 mole of aqueous solution of barium nitrate to produce 1 mole of solid barium sulfate and 2 moles of aqueous solution of sodium nitrate

Hence, the balanced molecular equation is written above.

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Use the tabulated half-cell potentials to calculate the equilibrium constant (K) for the following balanced redox reaction at 25
o-na [289]
The equation Eºcell = 0.0592/n logK must be used to find n and also Eºcell 
2 Al(s) + 3 Mg2+(aq) → 2 Al3+(aq) + 3 Mg(s) Al3+ +3e- --> Al Eº = -1.66 V Mg2+ +2e- -->Mg Eº = -2.37V 
To balance the equation, 6 moles of electrons must be transferred (2 Al and 3 Mg). This will be the value of n in the equation. 
To find Eºcell, you need the reduction potentials which should be given in a table, and given above. Eºcell = -1.66 - (-2.37) = 0.71 V log K = Eºcell x n/0.0592 = 0.71 x 6/0.0592 log K = 71.95 K = 10^71.95 K = 1.1x10^72
6 0
3 years ago
Which is most likely to happen during a precipitation reaction?
Salsk061 [2.6K]

Answer:

I think its B

Explanation:

Precipitation reactions leave a solid behind. The solid is called a precipitate.

3 0
3 years ago
What is the direction of the polarity of the indicated bond in h3c−oh marked by δ+ and δ−?
Sedbober [7]

Answer:- The direction of the polarity of the indicated bond is from carbon to oxygen.

Explanations:-  There are two types of covalent compounds, polar and non polar. If the bond is between two same atoms for example, H-H, Cl-Cl etc then the bond is non polar. If the bond is between two different atoms then the bond would be polar. The direction of the polarity is from loss electron negative atom to more electron negative atom.

Oxygen is more electron negative than carbon. So, being more electron negative, the bonding electrons are more towards oxygen and it cases partial negative charge on oxygen and partial positive charge on carbon. The direction of the polarity is from less electron negative carbon to more electron negative oxygen.

It is shown in the diagram below:


6 0
3 years ago
Determine % yield if a student obtains 45 g of product in an experiment and the theoretical amount is determined to be 50 g. *
ycow [4]

Answer:

90%

Explanation:

Percentage yield = ?

Theoretical yield = 50g

Actual yield = 45g

To calculate the percentage yield of a compound, we'll have to use the formula of percentage yield which is the ratio between the actual yield to theoretical multiplied by 100

Percentage yield = (actual yield / theoretical yield) × 100

Percentage yield = (45 / 50) × 100

Percentage yield = 0.9 × 100

Percentage yield = 90%

The percentage yield of the substance is 90%

6 0
3 years ago
Identify the species oxidized. 2 al3+(aq) + 2 fe(s) → 2 al(s) + 3 fe2+(aq)
Sliva [168]
To know the answer, compare the oxidation number of the element in the reactant and the product side. The oxidation number of Al was originally +3, then became 0 after the reaction. On the other hand, Fe was originally 0, then became +2 after the reaction. When the element is oxidized, it oxidation number increases. <em>Thus, the element oxidized is Fe.</em>
8 0
3 years ago
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