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Vinil7 [7]
2 years ago
12

Oil, with density of 900 kg/m3 and kinematic viscosity of 0.00001 m2/s, flows at 0.2 m3/s through 500 m of 200-mm-diameter cast-

iron pipe. determine (a) the head loss and (b) the pressure drop if the pipe slows down at 10o in the flow direction.
Engineering
1 answer:
Vsevolod [243]2 years ago
5 0
Just trying to personally understand this is making me shed a few tears. Good luck with finding someone to answer your question!
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Drum brakes are usually designed so that the condition of the lining can be checked even if the drum has not been
artcher [175]

Answer:

no it has to be removed

Explanation:

8 0
3 years ago
Technician A says that hoods are designed with reinforcements to prevent folding during a collision. Technician B says that some
-BARSIC- [3]

Technician A is wrong.

  • Usually, hoods have what is called "Crush Zones" underneath the panels. The function of the Crush Zone is to prevent the hoods, during a collision, from entering into the passenger space.

  • The crush zones allow the hoods to fold instead.

Technician B is right.

  • Automobile producers now make use of a hybrid form of hood that consists of fiberglass reinforced with plastic.

  • They are mostly used for trucks that have a low volume of production.

  • The hood is built using a process called Resin Transfer Model (RTM).

See the link below for more about automobile engineering:

brainly.com/question/4822721

6 0
2 years ago
A search will start from a visual lead<br> true<br> false
BlackZzzverrR [31]
True

An organized searching process will need to start from the visual lead area. Eye focus and eye movements from the path of travel in an organized pattern describes a visual search process.
4 0
2 years ago
Read 2 more answers
How to tie shoe please
Genrish500 [490]
Step 1: Unknot Shoelaces. Make sure that the two ends of the shoelace are completely untangled and free of knots past the tongue. ...
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4 0
2 years ago
The driveshaft of an automobile is being designed to transmit 134 hp at 2900 rpm. Determine the minimum diameter d required for
Misha Larkins [42]

Answer:

The minimum diameter is 1.344 in

Explanation:

The angular speed of the driveshaft is equal to:

w=\frac{2\pi N}{60}

Where

N = rotational speed of the driveshaft = 2900 rpm

w=\frac{2\pi *2900}{60} =303.69rad/s

The torque in the driveshaft is equal to:

\tau=\frac{P}{w}

Where

P = power transmitted by the driveshaft = 134 hp = 73700 lb*ft/s

\tau=\frac{73700}{303.69}  =242.68lb*ft

The minimum diameter is equal to:

d_{min} =(\frac{16T}{\pi *\tau } )^{1/3}

Where

T = shear stress = 6100 psi

τ = 242.68 lb*ft = 2912.16 lb*in

d_{min} =(\frac{16*2912.16}{\pi *6100} )^{1/3} =1.344in

4 0
3 years ago
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