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4 years ago

7

Each year, about _____ percent of the arctic sea ice moves south into the greenland sea, where it eventually breaks up and melts

away.

2 answers:

Mekhanik [1.2K]4 years ago

5 0

Its 10% its on quizlet

7nadin3 [17]4 years ago

3 0

10% is the answer to this question

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In a football game, a 96 kg receiver leaps straight up in the air to catch the 0.42 kg ball the quarterback threw to him at a vi

fredd [130]

Answer:

V = 0.074 m/s

Explanation:

given,

mass of the receiver, M = 96 Kg

mass of the ball, m = 0.42 Kg

initial speed of the ball, v = 17 m/s

initial speed of the receiver = 0 m/s

final speed.V = ?

using conservation of momentum

M u + m v = (M + m) V

0 + 0.42 x 17 = (96+0.42) V

96.42 V = 7.14

V = 0.074 m/s

hence, Speed after catching the ball is equal to 0.074 m/s

7 0

4 years ago

what is formed when two or more substances are so evenly mixed that you can't see the different parts

Andre45 [30]

A homogenous mixture

5 0

4 years ago

a man drags a 8.10 kg bag of mulch at a constant speed, applying a 29.5 N at 38°. what is the coefficient of friction?

lesantik [10]

Answer:

The coefficient of friction is 0.38.

Explanation:

The free body diagram is drawn below.

Let $f$ be frictional force acting in the backward direction as shown. Let the coefficient of friction be $\mu$ . Let $N$ be the normal reaction force acting on the bag.

Given:

Mass of the bag is, $m=8.10\textrm{ kg}$

Force acting at $\theta = 38$ ° is $F= 29.5\textrm{ N}$

Acceleration due to gravity is, $g=9.8\textrm{ }m/s^{2}$

The force F can be resolved into its components as $F_{x}=F \cos \theta$ and $F_{y}=F \sin \theta$

Therefore,

$F_{x}=29.5\cos(38)=23.25\textrm{ N}\\F_{y}=29.5\sin(38)=18.16\textrm{ N}$

Now, as there is no acceleration in vertical direction, therefore,

Sum of upward forces = Sum of downward forces

$N+F_{y}=mg\\N=mg-F_{y}=8.10\times 9.8-18.16\\N=79.38-18.16=61.22\textrm{ N}$

Now, as the bag is moving at a constant speed, so acceleration in the horizontal direction is also zero as acceleration is the rate of change of velocity.

Therefore, backward force = forward force.

$f=F_{x}\\f=23.25\textrm{ N}$

Now, frictional force is given as:

$f=\mu N\\\mu = \frac{f}{N}=\frac{23.25}{61.22}=0.38$

Therefore, the coefficient of friction is 0.38.

8 0

4 years ago

Energy transformed by a moving object is

QveST [7]

Kinetic energy is the energy an object has because of its motion. If we want to accelerate an object, then we must apply a force. ... Kinetic energy can be transferred between objects and transformed into other kinds of energy

4 0

4 years ago

A person pushes a 15.7-kg shopping cart at a constant velocity for a distance of 25.9 m on a flat horizontal surface. She pushes

valentinak56 [21]

Answer:

a) F = 35.7 N, b) W = 846.7 J, c) W = - 846.9 J, d) W=0

Explanation:

a) For this exercise let's use Newton's second law, let's set a reference frame with the x-axis horizontally

let's break down the pushing force.

cos (-23,7) = Fₓ / F

sin (-237) = F_y / F

Fₓ = F cos 23.7 = F 0.916

F_y = F sin (-23.7) = - F 0.402

Y axis

N- W - F_y = 0

N = W + F 0.402

X axis

Fₓ - fr = 0

F 0.916 = fr

F = fr / 0.916

F = 32.7 / 0.916

F = 35.7 N

It is asked to calculate several jobs

b) the work of the pushing force

W = fx x

W = 35.7 cos 23.7 25.9

W = 846.7 J

c) friction force work

W = F x cos tea

friction force opposes movement

W = - fr x

W = - 32.7 25.9

W = - 846.9 J

d) The work of the force would gravitate, as the displacement and the force of gravity are at 90º, the work is zero

W = 0

6 0

3 years ago