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stealth61 [152]
3 years ago
9

Maria is comparing data from an investigation about the melting point of ice. Based on her research, she knows ice

Physics
2 answers:
erica [24]3 years ago
8 0

Answer:

The answer Is set 4.

Explanation

eduard3 years ago
5 0

Answer:

set 2

Explanation:

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What does Kepler's first law of planetary motion imply?
BlackZzzverrR [31]

<u>Answer:</u>

The correct answer option is D.  The distance between the planet and the Sun changes as the planet orbits the sun.

<u>Explanation:</u>

Kepler’s laws of planetary motion, derived by the German astronomer Johannes Kepler, are the laws of physics that describe the motions of the planets in the solar system.

According to the Kepler's first law of planetary motion: the path on which the planets orbit around the sun is elliptical in shape, with the center of the sun at one focus.

Therefore, the distance between the Sun and the planets vary as the planet orbit around the sun.

6 0
3 years ago
30.6*X+-2.56<br> Pls help
pochemuha

Answer:  10.16

Explanation:

5 0
3 years ago
Suppose that a constant force is applied to an object. Newton's Second Law of Motion states that the acceleration of the object
omeli [17]
<span>(9 kg)(5 m/s^2) = M(3 m/s^2) 
</span><span>that the acceleration of the object varies inversely with its mass.</span>
4 0
3 years ago
A 0.49-kg cord is stretched between two supports, 7.8m apart. When one support is struck by a hammer, a transverse wave travels
katovenus [111]

To solve this problem we will apply the laws of Mersenne. Mersenne's laws are laws describing the frequency of oscillation of a stretched string or monochord, useful in musical tuning and musical instrument construction. This law tells us that the velocity in a string is directly proportional to the root of the applied tension, and inversely proportional to the root of the linear density, that is,

v = \sqrt{\frac{T}{\mu}}

Here,

v = Velocity

\mu= Linear density (Mass per  unit length)

T = Tension

Rearranging to find the Period we have that

T = v^2 \mu

T = v^2 (\frac{m}{L})

As we know that speed is equivalent to displacement in a unit of time, we will have to

T = (\frac{L}{t}) ^2(\frac{m}{L})

T = (\frac{7.8}{0.83})^2 (\frac{0.49}{7.8})

T = 5.54N

Therefore the tension is 5.54N

8 0
3 years ago
You toss a walnut at a speed of 15.0 m/s at an angle of 50.0∘ above the horizontal. The launch point is on the roof of a buildin
kaheart [24]

Answer:

a.3.51s

b.33.8m

c. 9.64,-22.9

Explanation:

8 0
2 years ago
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