C = Q/V, and since C is a constant, if voltage is doubled, charged will be doubled as well. Therefore charge will be 2Q
Answer:
Proof is given below
Explanation:
The length contraction is given by Δx = Δx' *√(1 - v² / c²)
where Δx' is the proper length and is measured in the frame where the object is at rest
Since the y' and z' axes are perpendicular to the direction of motion there is no contraction
So if you let V0 = Δy' * Δz' *Δx'
and V = Δy * Δz * Δx = Δy'* Δz' * Δx
Then
V = V0 * √(1 - v² / c²)
Answer:
the stored memory undergoes important changes, as revealed by the behavioral outcomes of its retrieval.
Explanation:
Answer:
There may be excess charges in the interior of the wire
The net electric field everywhere inside the wire is zero
The interior of the metal wire is neutral.
There may be excess charges on the surface of the wire.
There is no net flow of mobile electrons inside the wire.
Explanation:
For any metal wire in equilibrium position, there may be excess charges in the interior of the wire and the net electric field everywhere inside the wire is zero. Additionally, the interior of the metal wire is always neutral and there is likely to be excess charges on the surface of the wire. Moreover, it's important to note that for a metal wire in equilibrium, there is no net flow of mobile electrons inside the wire.
