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Lesechka [4]
3 years ago
12

Michael is playing with two horseshoe magnets. He is trying to get them to touch, but they will not regardless of how hard he tr

ies. Why will the magnets not come in contact?
Physics
2 answers:
Nesterboy [21]3 years ago
8 0
Since like poles repel, the two horseshoe magnets have like poles facing each other, hence they repel each other and therefore they will not come in contact
Alexus [3.1K]3 years ago
8 0
The reason the two horseshoe magnets wouldn't touch is because they are the same sides/ force. The saying of opposite attract becomes the opposite meaning, similar object repel. 
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A skydiver will reach a terminal velocity when the air drag equals their weight. For a skydiver with high speed and a large body
Andrej [43]

Answer with Explanation:

It is given that

1) Force of Drag F_{D}=\frac{1}{2}\rho Av^{2}

2) Weight W=mg

Equating drag and weight we get

F_{D}=W\\\\\frac{1}{2}\rho Av^{2}=mg\\\\v^{2}=\frac{2mg}{\rho A}\\\\\therefore v=\sqrt{\frac{2mg}{\rho _{air}A}}

where,

'm' is mass of the object

'g' is acceleration due to gravity

'A' is the area of the person

\rho _{air} is the density of air

Approximating the weight of a man to be 75 kg and area of man 0.8m^{2}

Applying the values in the  formula we get

v=\sqrt{\frac{2\times 75\times 9.81}{1.225\times 0.8}}

\therefore v=38.75m/s

6 0
3 years ago
How much work is done if a force of 20 N moves an object a distance of 6 m?​
Nesterboy [21]

Explanation:

W=F×s

w=20N×6m=120J

W=120J

3 0
3 years ago
A Van de Graaff generator is one of the original particle accelerators and can be used to accelerate charged particles like prot
Rzqust [24]

Answer:

595391.482946 m/s

3.21875\times 10^{6}

Explanation:

E = Energy = 1.85 keV

I = Current = 5.15 mA

e = Charge of electron = 1.6\times 10^{-19}\ C

t = Time taken = 1 second

m = Mass of proton = 1.67\times 10^{-27}\ kg

Velocity of proton is given by

v=\sqrt{\dfrac{2E}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 1.85\times 10^3\times 1.6\times 10^{-19}}{1.67\times 10^{-27}}}\\\Rightarrow v=595391.482946\ m/s

The speed of the proton is 595391.482946 m/s

Current is given by

I=\dfrac{\Delta Q}{t}\\\Rightarrow \Delta Q=It\\\Rightarrow \Delta Q=5.15\times 10^{-3}\times (1\ sec)\\\Rightarrow Q=5.15\times 10^{-3}\ C

Number of protons is

n=\dfrac{Q}{e}\\\Rightarrow n=\dfrac{5.15\times 10^{-3}}{1.6\times 10^{-19}}\\\Rightarrow n=3.21875\times 10^{6}\ protons

The number of protons is 3.21875\times 10^{6}

3 0
4 years ago
Which one of these is true about forces
zvonat [6]

Answer: D

Explanation:

8 0
2 years ago
Read 2 more answers
For the following statements, indicate whether the statement is true or false and explain in words your reasoning.
Nataly [62]

Answer:

a) If I increase the number of moving charged particles per cubic meter in a conductor, I will have to increase the cross sectional area of the conductor to get the same amount of current for the same electric field in the conductor.

FALSE

As we know that

I = neAv_d

so here if we increase the number of charge per unit volume then we need to decrease the area to get same amount of current through the wire.

b) The change in magnetic flux in a closed loop induces an EMF that opposes the change in magnetic flux.

TRUE

As per lenz law the direction of induced EMF is always opposite to the change in the flux due to which EMF is induced in the closed loop.

c) The magnetic force per unit length of two long, parallel, current-carrying conductors is repulsive if the currents are flowing in the opposite direction.

TRUE

When magnetic field of first wire will interact with other then it will exert force on it

so here the force will be on other wire such that the two wire will repel when current in the two wires is opposite in direction.

d) . The total magnetic flux through a closed surface is equal to μ0I enclosed

FALSE

magnetic flux is the number of field lines passing through a given area

So it is given as

B. A = 0

8 0
3 years ago
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