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Mkey [24]
3 years ago
9

A worker pushes horizontally on a 34 kg crate with a force of magnitude 110 n . the coefficient of static friction between the c

rate and the floor is 0.37. (a) what is the frictional force on the crate from the floor?
Physics
1 answer:
Vadim26 [7]3 years ago
4 0
<span>Static frictional force = 126.91 N 
1st worker force = 110 N 
2nd worker = 126.91 – 110 = 16.91 N</span>electron1 <span>· 7 years ago.</span>
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Answer:

It is an example of negative feedback mechanism

Explanation:

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a projectile is fired in such away that its horizontal range is equal to three times its naximum height.what is the angle of pro
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Answer:

\theta=53.13^o

Explanation:

<u>2-D Projectile Motion</u>

In 2-D motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration, while the acceleration in the vertical direction is always the acceleration due to gravity. The basic formulas for this type of movement are

V_x=V_{ox}=V_ocos\theta

V_y=V_{oy}-gt=V_osin\theta-gt

x=V_{ox}t

\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}

\displaystyle x_{max}=\frac{2V_{ox}V_{oy}}{g}

\displaystyle y_{max}=\frac{V_{oy}^2}{2g}

The projectile is fired in such a way that its horizontal range is equal to three times its maximum height. We need to find the angle \theta at which the object should be launched. The range is the maximum horizontal distance reached by the projectile, so we establish the base condition:

x_{max}=3y_{max}

\displaystyle \frac{2V_{ox}V_{oy}}{g}=3\frac{V_{oy}^2}{2g}

Using the formulas for V_{ox}, V_{oy}:

\displaystyle \frac{2V_{o}cos\theta V_{o}sin\theta}{g}=3\frac{V_{o}^2sin^2\theta}{2g}

Simplifying

4cos\theta sin\theta=3sin^2\theta

Dividing by sin\theta

4cos\theta=3sin\theta

Rearranging

tan\theta=\frac{4}{3}

\theta=arctan\frac{4}{3}

\theta=53.13^o

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3 years ago
A horizontal line on a distance-time graph means the object is
IgorLugansk [536]
At rest because if the distance is not changing, then it is not moving any further, so it must not be moving! The time keeps going no matter what, so the distance, whether it is 0 m or 10,000 km, if the y is horizontal the distance does not change. 
6 0
4 years ago
Why is sun called a source of light??​
mote1985 [20]

Answer:

because he give heat and energy

3 0
3 years ago
A positive charge of 8.0 × 10-4 C is in an electric field that exerts a force of 3.5 × 10-4 N on it. What is the strength of the
Gennadij [26K]

Answer:

E = 0.437 N/C

Explanation:

Given that,

Charge, q=8\times 10^{-4}\ C

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Let the strength of the electric field is E. We know that, the electric force is given by :

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So, the strength of the electric field is equal to 0.437 N/C.

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3 years ago
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