Question

a 2 kg object is moving 6m/s. it compresses a spring 1 meter that has a spring constant of 8N/m. Calculate efficiency?

Answer 1

Answer:

The efficiency is 11.1%

Explanation:

Define efficiency as (energy stored in the spring) / (kinetic energy of the object before compression)*100%.

The moving object had a kinetic energy

The compressed spring stores a so-called elastic energy, which is given by

So the efficiency is: 11.1

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Answer 2

Answer:

The efficiency is $11.\overline{1}\%$

Explanation:

Define efficiency as (energy stored in the spring) / (kinetic energy of the object before compression)*100%.

The moving object had a kinetic energy

$E_k = \frac{1}{2}mv^2=\frac{1}{2}2kg\cdot 36 \frac{m^2}{s^2}=36J$

The compressed spring stores a so-called elastic energy, which is given by

$E_e=\frac{1}{2}kd^2=\frac{1}{2}8\frac{N}{m}\cdot 1^2m^2=4J$

So the efficiency is:

$\epsilon = \frac{E_e}{E_k}\cdot100\%=\frac{4J}{36J}\cdot 100\%=11.\overline{1}\%$