Answer:
0.31%
Explanation:
The acceleration due to gravity at sea level is:
g = GM / R²
where G is the gravitational constant, M is the mass of Earth, and R is the radius of the Earth.
The acceleration due to gravity a height h above sea level is:
g' = GM / (R+h)²
The percent variation is:
(g − g') / g
= 1 − g'/g
= 1 − [GM / (R+h)²] / [GM / R²]
= 1 − R² / (R+h)²
= 1 − (R / (R+h))²
The average radius of the Earth is 6370 km. The height of the balloon is 10 km.
1 − (6370 / (6370 + 10))²
0.0031
0.31%
Answer:
Time of race = 10.18 s
Explanation:
She keeps this acceleration for 17 m and then maintains the velocity for the remainder of the 100-m dash
Time to travel 17 m can be calculated
s = ut + 0.5at²
17 = 0 x t + 0.5 x 3.89 x t²
t = 2.96 s
Velocity after 2.96 seconds
v = 3.89 x 2.96 = 11.50 m/s
Remaining distance = 100 - 17 = 83 m
Time required to cover 83 m with a speed of 11.50 m/s

Time of race = 2.96 + 7.22 = 10.18 s
Answer:
Explanation:
Given
Length of cable 
Diameter of cable 
time taken to return to original position 
time taken to cover distance L

velocity

(b)Relation between velocity of wave Tension is
mass per unit Length



where 



Answer:
The time taken for the package to reach the ground is 20.6s
Explanation:
Given that the formula of distance is D = S×T where S represents soeed and T is time. So you have to substitute the following values into the formula :






Given:
k = 100 lb/ft, m = 1 lb / (32.2 ft/s) = 0.03106 slugs
Solution:
F = -kx
mx" = -kx
x" + (k/m)x = 0
characteristic equation:
r^2 + k/m = 0
r = i*sqrt(k/m)
x = Asin(sqrt(k/m)t) + Bcos(sqrt(k/m)t)
ω = sqrt(k/m)
2π/T = sqrt(k/m)
T = 2π*sqrt(m/k)
T = 2π*sqrt(0.03106 slugs / 100 lb/ft)
T = 0.1107 s (period)
x(0) = 1/12 ft = 0.08333 ft
x'(0) = 0
1/12 = Asin(0) + Bcos(0)
B = 1/12 = 0.08333 ft
x' = Aω*cos(ωt) - Bω*sin(ωt)
0 = Aω*cos(0) - (1/12)ω*sin(0)
0 = Aω
A = 0
So B would be the amplitude. Therefore, the equation of motion would be x
= 0.08333*cos[(2π/0.1107)t]