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lozanna [386]
3 years ago
8

A nuclear fission reactor produces electricity. What is the role of the fuel, the control rods, water, and generator in this pro

cess?
A reactor core full of water is heated to steam by the fission reaction that occurs inside control rods full of radioactive fuel pellets. The generator collects the emitted particles as the radioactive nuclei collide and transfers them to the power grid.

Fuel rods heat a pool of water to steam as heat from the fission reaction of the yellowcake inside is transferred to the water. The control rods are used to control the rate of electricity leaving the generator as it converts mechanical energy from a steam-powered turbine into electrical energy.

A generator is used to activate the control rods which contain radioactive isotopes. Once activated, these isotopes begin a nuclear fission chain reaction. Water in a cooling tank keeps the rate of reaction under control as electrons emitted from the reaction are fed through wires to homes and businesses.

The radioactive isotopes used as fuel provide the heat energy to create steam from water through a nuclear fission chain reaction. The control rods are used to regulate the rate of this fission reaction. The generator converts mechanical energy from a steam-powered turbine into electricity.
Physics
2 answers:
77julia77 [94]3 years ago
8 0

Answer:Correct Answer:  

Correct The radioactive isotopes used as fuel provide the heat energy to create steam from water through a nuclear fission chain reaction. The control rods are used to regulate the rate of this fission reaction. The generator converts mechanical energy from a steam-powered turbine into electricity.



Explanation: VERIFIED

natima [27]3 years ago
7 0
The appropriate response is the third one. A generator is utilized to enact the control poles which contain radioactive isotopes. Once initiated, these isotopes start an atomic splitting chain response. Water in a cooling tank monitors the rate of response as electrons radiated from the response are encouraged through wires to homes and organizations.
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Explanation:

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2 years ago
You are going 30 m/s in a car of mass 1000 kg when you reach a red light and stop your car.
Radda [10]

Answer:

Explanation:

The kinetic energy will convert to heat energy (provided the car has friction brakes and not regenerative brakes as might be found on an electric or hybrid) Also<u> assuming level road</u>.

E = ½mv² = ½(1000)30² = 450,000 J

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2 years ago
What will the magnitude of the field be if the 10 nc charge is replaced by a 20 nc charge? Assume the system is big enough to co
MArishka [77]

Answer:

Same magnitude of the 10 nc charge cause the electric field is external.

Explanation:

To do a better explanation, let's go and suppose we have an electric field of, 1300 N/C with a 10 nC charge.

As the system we are talking about is really big, and the charge is small, we can assume always if the charge is sitting right in the same point where the electric field is, then, the electric field would not suffer any kind of alteration in it's value. Therefore, no matter what value of the charge is sitting here, the electric field is independent of the charge, so it would not feel any alteration. However, the force that the charge is feeling would be stronger than in the first case.

F = qE

If charge is doubled, then the force would be bigger in the second case than in the first case, but electric field remain the same value.

4 0
2 years ago
how much time would it take for the sound of thunder to travel 1,500 meters if sound travels at a speed of 330m/s
user100 [1]

Answer:

4.545454 seconds

Explanation:

1500/330=4.545454 seconds

5 0
3 years ago
Read 2 more answers
How many photons strike the cd surface during the playing of a cd 69 minutes in length?
Reptile [31]

Answer:

Photons strike the CD n=1.624 x10^{18}

Explanation:

First of all, it is necessary to calculate the energy produced by a semiconductor laser for 69 minutes:

69minutes*\frac{60s}{1 minute}=4140s

E=0.1x10^{-3}w*4140s=0.414J

Next, it is possible to calculate the number of photons striking the CD surface during this time:

E=\frac{n*h*c}{l}

l=780x10^{-9}m long in CD

c=3x10^8 m/s light velocity

h=6.626x10^{-34} J*s

Solve to n'

n=\frac{E*l}{c*h}=\frac{0.414 J*780x10^{-9}m}{3x10^8m/s*6.626x10^{-34}}

n=1.624 x10^{18}

8 0
2 years ago
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