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lozanna [386]
3 years ago
8

A nuclear fission reactor produces electricity. What is the role of the fuel, the control rods, water, and generator in this pro

cess?
A reactor core full of water is heated to steam by the fission reaction that occurs inside control rods full of radioactive fuel pellets. The generator collects the emitted particles as the radioactive nuclei collide and transfers them to the power grid.

Fuel rods heat a pool of water to steam as heat from the fission reaction of the yellowcake inside is transferred to the water. The control rods are used to control the rate of electricity leaving the generator as it converts mechanical energy from a steam-powered turbine into electrical energy.

A generator is used to activate the control rods which contain radioactive isotopes. Once activated, these isotopes begin a nuclear fission chain reaction. Water in a cooling tank keeps the rate of reaction under control as electrons emitted from the reaction are fed through wires to homes and businesses.

The radioactive isotopes used as fuel provide the heat energy to create steam from water through a nuclear fission chain reaction. The control rods are used to regulate the rate of this fission reaction. The generator converts mechanical energy from a steam-powered turbine into electricity.
Physics
2 answers:
77julia77 [94]3 years ago
8 0

Answer:Correct Answer:  

Correct The radioactive isotopes used as fuel provide the heat energy to create steam from water through a nuclear fission chain reaction. The control rods are used to regulate the rate of this fission reaction. The generator converts mechanical energy from a steam-powered turbine into electricity.



Explanation: VERIFIED

natima [27]3 years ago
7 0
The appropriate response is the third one. A generator is utilized to enact the control poles which contain radioactive isotopes. Once initiated, these isotopes start an atomic splitting chain response. Water in a cooling tank monitors the rate of response as electrons radiated from the response are encouraged through wires to homes and organizations.
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In a balloon adventure, you reach 10 km in height. Find the percentage variation in the weight of the balloon-crew system with r
Dmitriy789 [7]

Answer:

0.31%

Explanation:

The acceleration due to gravity at sea level is:

g = GM / R²

where G is the gravitational constant, M is the mass of Earth, and R is the radius of the Earth.

The acceleration due to gravity a height h above sea level is:

g' = GM / (R+h)²

The percent variation is:

(g − g') / g

= 1 − g'/g

= 1 − [GM / (R+h)²] / [GM / R²]

= 1 − R² / (R+h)²

= 1 − (R / (R+h))²

The average radius of the Earth is 6370 km.  The height of the balloon is 10 km.

1 − (6370 / (6370 + 10))²

0.0031

0.31%

8 0
3 years ago
A 64.9 kg sprinter starts a race with an acceleration of 3.89 m/s2. She keeps this acceleration for 17 m and then maintains the
xxMikexx [17]

Answer:

Time of race  = 10.18 s

Explanation:

She keeps this acceleration for 17 m and then maintains the velocity for the remainder of the 100-m dash

Time to travel 17 m can be calculated

         s = ut + 0.5at²

         17 = 0 x t + 0.5 x 3.89 x t²

          t = 2.96 s

Velocity after 2.96 seconds

          v = 3.89 x 2.96 = 11.50 m/s

Remaining distance = 100 - 17 = 83 m

Time required to cover 83 m with a speed of 11.50 m/s

          t=\frac{83}{11.50}=7.22s

Time of race = 2.96 + 7.22 = 10.18 s

3 0
3 years ago
A ski gondola is connected to the top of a hill by a steel cable oflength 620 m and diameter 1.5 cm. As thegondola comes to the
klemol [59]

Answer:

Explanation:

Given

Length of cable L=620 m

Diameter of cable d=1.5 cm

time taken to return to original position T=14 s

time taken to cover distance L

t=\frac{T}{2}=7 s

velocity

v=\frac{L}{t}=\frac{620}{7}=88.57 m/s

(b)Relation between velocity of wave Tension is

v=\sqrt{\frac{T}{\mu }} , where \mu =mass per unit Length

T=v^2\cdot \mu

T=(88.57)^2\cdot \frac{m}{L}

T=(88.57)^2\cdot \frac{\rho AL}{L}

where \rho =density\ of\ steel =7850 kg/m^3

A=area\ of\ cross-section=\frac{\pi }{4}d^2=1.76\times 10^{-4} cm^2

T=(88.57)^2\cdot 7850\times 1.76\times 10^{-4}

T=10,883 N

5 0
3 years ago
A helicopter is ascending vertically with a speed of 5.10m/s. At a height of 105 m above the Earth, a package is dropped from a
Oksi-84 [34.3K]

Answer:

The time taken for the package to reach the ground is 20.6s

Explanation:

Given that the formula of distance is D = S×T where S represents soeed and T is time. So you have to substitute the following values into the formula :

distance = speed \times time

let \: distance = 105 \\ let \: speed = 5.10

105 = 5.1 \times t

5.1t = 105

t = 105 \div 5.1

t = 20.6 \: second \: (3s.f)

7 0
3 years ago
A spring with a spring constant kk of 100 pounds per foot is loaded with 1-pound weight and brought to equilibrium. it is then s
tino4ka555 [31]

Given:

k = 100 lb/ft, m = 1 lb / (32.2 ft/s) = 0.03106 slugs 

Solution:


F = -kx 
mx" = -kx 
x" + (k/m)x = 0 

characteristic equation: 
r^2 + k/m = 0 
r = i*sqrt(k/m) 

x = Asin(sqrt(k/m)t) + Bcos(sqrt(k/m)t) 

ω = sqrt(k/m) 
2π/T = sqrt(k/m) 
T = 2π*sqrt(m/k) 
T = 2π*sqrt(0.03106 slugs / 100 lb/ft) 
T = 0.1107 s (period) 

x(0) = 1/12 ft = 0.08333 ft 
x'(0) = 0 

1/12 = Asin(0) + Bcos(0) 
B = 1/12 = 0.08333 ft 

x' = Aω*cos(ωt) - Bω*sin(ωt) 
0 = Aω*cos(0) - (1/12)ω*sin(0) 
0 = Aω 
A = 0 

So B would be the amplitude. Therefore, the equation of motion would be x = 0.08333*cos[(2π/0.1107)t]

5 0
3 years ago
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