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3 years ago

How are earth and venus similar and different?

1 answer:

soldier1979 [14.2K]3 years ago

6 0

Similarities would be
They are both made of rock.
They are close in size.
They both have thick atmospheres.
They both have similar densities.
The strength of the gravity on their surfaces is similar.

Differences would be Venus and Earth are planets in our solar system, with Venus being the second closest planet and the Earth being the third closest to the sun. The mass of the earth is about 1.23 times the mass of Venus.

Being closer to the sun, Venus is a lot hotter than the Earth. While the average temperature on the earth is about 14 °C, that on Venus is over 460 °C. . Hope that helps

You might be interested in

The surface tension of water was determuned in a laboratory by using the drop weight method. 100 drops were released from a bure

lana [24]

Answer:

The surface tension of the water is 6.278×10⁻² N/m

error = 13.65%

Explanation:

The surface tension of water is given by

$\gamma = \frac{F}{L}$

Where F is the force acting on water and L is the length over which is force is acted.

We are given the mass of 100 droplets of water

M = 3.78 g

n = 100

The mass of 1 droplet is given by

$m = \frac{M}{n} \\\\m = \frac{3.78}{100}\\\\m = 0.0378 \: g \\\\m = 3.780\times10^{-5} \: kg$

The force acting on a single droplet of water is given by

$F = m \cdot g$

Where m is the mass of water droplet and g is the acceleration due to gravity

$F = 3.780\times10^{-5} \cdot 9.81$

$F = 3.708\times10^{-4} \: N$

The circumferential length of the droplet is given by

$L = \pi \cdot d$

Where d is the diameter

$L = \pi \cdot 1.88\times10^{-3}\\\\L = 5.906 \times10^{-3} \: m$

Now we can find out the required surface tension of the water

$\gamma = \frac{3.708\times10^{-4} }{5.906 \times10^{-3}} \\\\\gamma = 0.06278\: N/m\\\\\gamma = 6.278 \times10^{-2} \: N/m\\\\$

Therefore, the surface tension of the water is 6.278×10⁻² N/m

The tabulated value of the surface tension of water at 20 °C is given by

$\gamma_t = 0.0727 \: N/m$

The percentage error between tabulated and calculated surface tension is given by

$error = \frac{\gamma_t - \gamma }{\gamma_t}$

$error = \frac{ 0.0727 - 0.06278}{0.0727} \times 100\%$

$$ error = 13.65 \%$

7 0

3 years ago

A current of 0.92 a flows in a wire. how many electrons are flowing past any point in the wire per second? the charge on one ele

Fantom [35]

The current is defined as the ratio between the charge Q flowing through a certain point of a wire and the time interval, $\Delta t$ :
$I= \frac{Q}{\Delta t}$
First we need to find the net charge flowing at a certain point of the wire in one second, $\Delta t=1.0 s$ . Using I=0.92 A and re-arranging the previous equation, we find
$Q=I \Delta t= (0.92 A)(1.0 s)=0.92 C$

Now we know that each electron carries a charge of $e=1.6 \cdot 10^{-19} C$ , so if we divide the charge Q flowing in the wire by the charge of one electron, we find the number of electron flowing in one second:
$N= \frac{Q}{q} = \frac{0.92 C}{1.6 \cdot 10^{-19} C}=5.75 \cdot 10^{18}$

3 0

3 years ago

Lamar writes several equations trying to better understand potential energy. What conclusion is best supported by lamar's worm?

kumpel [21]

Complete question is;

Lamar writes several equations trying to better understand potential energy. What conclusion is best supported by Lamar’s work?

A) The elastic potential energy is the same for any distance from a reference point.

B) The gravitational potential energy equals the work needed to lift the object.

C) The gravitational potential energy is the same for any distance from a reference point.

D) The elastic potential energy equals the work needed to stretch the object

Answer:

B) The gravitational potential energy equals the work needed to lift the object.

Explanation:

In physics, we know that potential energy is the energy of a body at rest while the energy of a body in motion is known as kinetic energy.

However,the work required to lift a body from it's position of rest is equal to the Gravitational potential energy of that body.

Elastic potential energy is the one that is stored as a result of force applied to deform an elastic object. Thus, it is not equal to the work needed to stretch the object and it is also not the same for any distance from reference point.

Thus, looking at the options, Option B is correct

6 0

3 years ago

Light travelling in one material enters another material in which it travels faster. The light wave will:

Free_Kalibri [48]

The light will change its direction and bend away from the normal.

8 0

4 years ago

The eyepiece of a light microscope has a magnification level of 10x. If you were looking at a paramecium under the lowest-power

tester [92]

Answer:

The total magnification will be 40x.

Explanation:

As we know if the magnification of the eyepiece of a microscope be $m_{e}$ and that of the objective be $m_{o}$ , then the total magnification is given by

$m = m_{e} \times m_{o}$

Given, $m_{e} = 10x$ and $m_{o} = 4x$

Therefore total magnification is $m = 10 \times 4 = 40x$

4 0

3 years ago