Answer:
0.555 mol of aspirin
Explanation:
Given,
Mass of aspirin = 100 g
Molar mass of aspirin = 180.2 g/mol
To find, moles of aspirin in 100 g of mass = ?
The formula for the calculation of moles is shown below:
Thus,
Moles of aspirin in 100 g = 0.555 moles
Explanation: c= 1.2 mol/l (concentration ) and V = volume.
Amount of substance n= cV. Also n = mass/ molar mass m/M.
You need further information to solve the problem.
Either mass or amount of substance of HNO3 Is missing
Answer:
I don t no I'm in 7 class plz ask easy questions to me ok
Explanation:
(A) Manganese salts give a grey borax bead test in reducing flame.
(B) From a mixed precipitate of AgCl and AgI, ammonia solution dissolves only AgCl due to the formation of [Ag(NH
3
)
2
]Cl.
(C) Ferric ions give a prussian blue precipitate on adding potassium ferrocyanide solution (D). On boiling the solution having K
+
, Ca
2+
, and HCO
3
−
ions, we does not get a precipitate of K
2
Ca(CO
3
)
2
The balanced chemical equation for the above reaction is as follows ;
Mg + 2HCl —> MgCl2 + H2
The stoichiometry of Mg to HCl is 1:2
This means that 1 mol of Mg reacts with 2 mol of HCl
Equal amounts of both Mg and HCl have been added. One reagent is the limiting reactant and other reactant is in excess.
Limiting reactant is the reagent that is fully used up in the reaction and the amount of Product formed depends on the amount of limiting reactant present.
In this reaction if Mg is the limiting reactant, 4.40 moles of Mg should react with 4.40x2 -8.80 moles of HCl.
But only 4.40 moles of HCl present therefore HCl is the limiting reactant that reacts with 4.40/2 = 2.20 moles of Mg
Stoichiometry of HCl to MgCl2 is 2:1
Since HCl moles reacted -4.40 mol
Then MgCl2 moles formed are 4.40/2 = 2.20 mol of MgCl2