How many moles of Fe3O4 are required to supply enough iron to prepare 0.472mol Fe2O3 ?
1 answer:
The combustion reaction for Fe₃O₄ in an oxygen molecule O₂ yields Fe₂O₃.
The number of moles of Fe₃O₄ required to prepare 0.472 moles of Fe₂O₃ is:
0.315 moles
The reaction equation is:
From the above reaction;
4 moles of Fe₃O₄ react with oxygen to produce 6 moles Fe₂O₃.
i.e.
Fe₃O₄ : Fe₂O₃ = 4 : 6
Fe₃O₄ : Fe₂O₃ = 2 : 3
= 0.315 moles
Therefore, we can conclude that 0.472 moles of Fe₂O₃ are prepared from 0.315 moles of Fe₃O₄.
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The question is incomplete, complete question is :
A chemist must dilute 73.9 mL of 400 mM aqueous sodium carbonate solution until the concentration falls to 125 mM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.
Answer:
The final volume of the solution will be 0.236 L.
Explanation:
Concentration of sodium carbonate solution before dilution =
Volume of sodium carbonate solution before dilution =
Concentration of sodium carbonate solution after dilution =
Volume of sodium carbonate solution after dilution =
Dilution equation is given by:
1 mL = 0.001 L
236 mL = 0.236 L
The final volume of the solution will be 0.236 L.