Question

How many moles of Fe3O4 are required to supply enough iron to prepare 0.472mol Fe2O3 ?

Answer 1

The combustion reaction for Fe₃O₄ in an oxygen molecule O₂ yields Fe₂O₃.

The number of moles of Fe₃O₄ required to prepare 0.472 moles of Fe₂O₃ is:

0.315 moles

The reaction equation is:

$\mathbf{4Fe_3O_4+O_2 \to 6Fe_2O_3}$

From the above reaction;

4 moles of Fe₃O₄ react with oxygen to produce 6 moles Fe₂O₃.

i.e.

Fe₃O₄ : Fe₂O₃ = 4 : 6

Fe₃O₄ : Fe₂O₃ = 2 : 3

$\mathbf{ = \dfrac{2}{3}\times 0.472}$

= 0.315 moles

Therefore, we can conclude that 0.472 moles of Fe₂O₃ are prepared from  0.315 moles of  Fe₃O₄.

Learn more about chemical reactions here:

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