Answer:
2,7 m
Explanation:
You can solve this doing an energy balance:
Solving this equation to get h:
Replacing the values and solving brings to 2,7 m
How many moles of Fe3O4 are required to supply enough iron to prepare 0.472mol Fe2O3 ?
1 answer:
The combustion reaction for Fe₃O₄ in an oxygen molecule O₂ yields Fe₂O₃.
The number of moles of Fe₃O₄ required to prepare 0.472 moles of Fe₂O₃ is:
0.315 moles
The reaction equation is:
From the above reaction;
4 moles of Fe₃O₄ react with oxygen to produce 6 moles Fe₂O₃.
i.e.
Fe₃O₄ : Fe₂O₃ = 4 : 6
Fe₃O₄ : Fe₂O₃ = 2 : 3
= 0.315 moles
Therefore, we can conclude that 0.472 moles of Fe₂O₃ are prepared from 0.315 moles of Fe₃O₄.
Learn more about chemical reactions here:
You might be interested in
Explanation:
As density is defined as the mass of a substance divided by its volume.
Mathematically, Density =
It is given that mass is 50 g and density is 0.934 .
Hence, calculate the volume of methyl acetate as follows.
Density =
0.934 =
Volume =
or, = (as 1
= 1 mL)
Thus, we can conclude that the volume of methyl acetate the student should pour out is .