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Alekssandra [29.7K]

3 years ago

7

How are the Earth's crust and jigsaw alike?

2 answers:

Neporo4naja [7]3 years ago

4 0

The earth's surface is composed tectonic plates of basaltic oceanic crust with lighter granitic continental crust floating in isostatic balance on the oceanic crust.<span>
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Blizzard [7]3 years ago

4 0

The earths surface is composed tectonic plates of basaltic oceanic crust with lighter granitic continental crust floating in isostatic balance on the oceanic crust.

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HELP!! An illustration of a pendulum at 3 positions of a pendulum. The equilibrium position is labeled B. The other two position

zmey [24]

Answer

the answer is A and c

Explanation:

i got it right on edge

5 0

2 years ago

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What is the equivalent of 0° C in Kelvin?<br> Help will give brainiest

givi [52]

Answer:

273.15 dat is the answer im pretty sure

8 0

3 years ago

A 10-cm-long spring is attached to theceiling. When a 2.0 kg mass is hung from it,the spring stretches to a length of 15 cm.a.Wh

alekssr [168]

(a) 392 N/m

Hook's law states that:

$F=k\Delta x$ (1)

where

F is the force exerted on the spring

k is the spring constant

$\Delta x$ is the stretching/compression of the spring

In this problem:

- The force exerted on the spring is equal to the weight of the block attached to the spring:

$F=mg=(2.0 kg)(9.8 m/s^2)=19.6 N$

- The stretching of the spring is

$\Delta x=15 cm-10 cm=5 cm=0.05 m$

Solving eq.(1) for k, we find the spring constant:

$k=\frac{F}{\Delta x}=\frac{19.6 N}{0.05 m}=392 N/m$

(b) 17.5 cm

If a block of m = 3.0 kg is attached to the spring, the new force applied is

$F=mg=(3.0 kg)(9.8 m/s^2)=29.4 N$

And so, the stretch of the spring is

$\Delta x=\frac{F}{k}=\frac{29.4 N}{392 N/m}=0.075 m=7.5 cm$

And since the initial lenght of the spring is

$x_0 = 10 cm$

The final length will be

$x_f = x_0 +\Delta x=10 cm+7.5 cm=17.5 cm$

8 0

3 years ago

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Which substance is a greenhouse gas that is emitted by human activities, is the most widespread, and remains in the air the long

e-lub [12.9K]

Answer:

I am not really sure, but it is probably Carbon Dioxide

Explanation:

3 0

3 years ago

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If an object travels at a constant speed in a circular path, the acceleration of the object is:

Vilka [71]

Answer:

1- The acceleration of the object is larger in magnitude the smaller the radius of the circle.

Explanation:

The acceleration of an object in a circular path is

$a = \frac{v^2}{r}$

As can be seen from the equation, if the radius of the circle is decreases, the magnitude of the acceleration increases.

As for the direction of the acceleration, it is always towards the center, and it is always perpendicular to the direction of the velocity.

6 0

3 years ago