True a vector quantity has direction and a scalar quantity does not.
I think the correct answer from the choices listed above is option D. The difference between a chemical change and a physical change is lies in the fact that a physical change does not break any bonds while a chemical change does form new substances. Hope this answers the question.
For a simple harmonic motion energy is given with:

Where k is a constant that depends on the type of the wave you are looking at and A is amplitude.
Let's calculate the energy of the wave using two different amplitudes given in the problem:

We can see that energy associated with the wave is 4 times smaller when we decrease its amplitude by half. So the answer should be C.
Answer:


Given:
Initial velocity (u) = 0 m/s
Final velocity (v) = 20 m/s
Time taken (t) = 10 sec
To Find:
(i) Acceleration (a)
(ii) Distance covered (s)
Explanation:












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