¡los alienígenas son reales!
Combination, decomposition, single displacement, double displacement, etc.
I hope this helped!
The crate is in equilibrium. Newton's second law gives
∑ <em>F</em> (vertical) = <em>n</em> - <em>mg</em> = 0
∑ <em>F</em> (horizontal) = <em>p</em> - <em>f</em> = 0
where
• <em>n</em> = magnitude of the normal force
• <em>mg</em> = weight of the crate
• <em>p</em> = mag. of push exerted by movers
• <em>f</em> = mag. of kinetic friciton, with <em>f</em> = 0.60<em>n</em>
<em />
It follows that
<em>p</em> = <em>f</em> = 0.60<em>mg</em> = 0.60 (43.0 kg) <em>g</em> = 252.84 N
so that the movers perform
<em>W</em> = <em>p</em> (10.4 m) ≈ 2600 J
of work on the crate. (The <em>total</em> work done on the crate, on the other hand, is zero because the net force on the crate is zero.)
Answer:
<h3>The answer is 1.92 g/cm³</h3>
Explanation:
The density of a substance can be found by using the formula
![density = \frac{mass}{volume} \\](https://tex.z-dn.net/?f=density%20%3D%20%20%5Cfrac%7Bmass%7D%7Bvolume%7D%20%5C%5C)
From the question
mass = 2.5 g
Volume = 1.3 cm³
We have
![density = \frac{2.5}{1.3} \\ = 1.923076...](https://tex.z-dn.net/?f=density%20%3D%20%20%5Cfrac%7B2.5%7D%7B1.3%7D%20%20%5C%5C%20%20%3D%201.923076...)
We have the final answer as
<h3>1.92 g/cm³</h3>
Hope this helps you
Answer:
(A) 2652.49 ohm (b) 91937.45311 Hz (c) (i) 12.022 A (II) 2.324 A
Explanation:
We have given resistance R = 10 ohm
Capacitance C = 1 nF
Inductance of the coil L = 3 mH
(A) Inductive reactance ![X_L=\omega L=377\times 3\times 10^{-3}=1.131ohm](https://tex.z-dn.net/?f=X_L%3D%5Comega%20L%3D377%5Ctimes%203%5Ctimes%2010%5E%7B-3%7D%3D1.131ohm)
Capacitive reactance ![X_C=\frac{1}{\omega C}=\frac{1}{377\times 10^{-9}}=2.6525\times 10^6ohm](https://tex.z-dn.net/?f=X_C%3D%5Cfrac%7B1%7D%7B%5Comega%20C%7D%3D%5Cfrac%7B1%7D%7B377%5Ctimes%2010%5E%7B-9%7D%7D%3D2.6525%5Ctimes%2010%5E6ohm)
Impedance ![Z=\sqrt{R^2+(X_C-X_L)^2}=\sqrt{10^2+(2652500-1.131)^2}=2652.49ohm](https://tex.z-dn.net/?f=Z%3D%5Csqrt%7BR%5E2%2B%28X_C-X_L%29%5E2%7D%3D%5Csqrt%7B10%5E2%2B%282652500-1.131%29%5E2%7D%3D2652.49ohm)
(b) We know that resonance frequency ![f=\frac{1}{2\pi \sqrt{LC}}=\frac{1}{2\pi \sqrt{3\times 10^{-3}\times 10^{-9}}}=91937.45311Hz](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B1%7D%7B2%5Cpi%20%5Csqrt%7BLC%7D%7D%3D%5Cfrac%7B1%7D%7B2%5Cpi%20%5Csqrt%7B3%5Ctimes%2010%5E%7B-3%7D%5Ctimes%2010%5E%7B-9%7D%7D%7D%3D91937.45311Hz)
(c) (i) At resonance condition
so only effective resistance is R
So maximum current ![i=\frac{V}{R}=\frac{\frac{170}{\sqrt{2}}}{10}=12.022A](https://tex.z-dn.net/?f=i%3D%5Cfrac%7BV%7D%7BR%7D%3D%5Cfrac%7B%5Cfrac%7B170%7D%7B%5Csqrt%7B2%7D%7D%7D%7B10%7D%3D12.022A)
(ii) Current across the coil ![i=\frac{voltage\ across\ the\ coil}{impedence\ of\ the\ coil}=\frac{\frac{3}{\sqrt{2}}}{1.131}=2.324A](https://tex.z-dn.net/?f=i%3D%5Cfrac%7Bvoltage%5C%20across%5C%20the%5C%20coil%7D%7Bimpedence%5C%20of%5C%20the%5C%20coil%7D%3D%5Cfrac%7B%5Cfrac%7B3%7D%7B%5Csqrt%7B2%7D%7D%7D%7B1.131%7D%3D2.324A)