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2 years ago

Describe and explain the stages of making copper chloride crystals and acid.

Chemistry

2 answers:

bulgar [2K]2 years ago

6 0

Answer:

Add excess copper carbonate to hydrochloric acid in a beaker, stirring until there is no further reaction. Filter the mixture to remove the remaining copper carbonate, then heat the remaining solution to the point of crystallisation. Leave the solution to cool and collect the crystals formed by filtration.

Explanation:

yKpoI14uk [10]2 years ago

6 0

Answer:

CHICKEN

Explanation:

EGG

LEG

PIC

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The equilibrium constant in terms of pressure. Kp for the following process is 0.179 at 50 °C. It increases to 0.669 at 86 °C. C

Vikentia [17]

Answer:

a) ΔHvap=35.3395 kJ/mol

b) Tb=98.62 °C

Explanation:

Given the reaction:

C₇H₁₆ (l) ⇔ C₇H₁₆ (g)

Kp=P(C₇H₁₆) since the concentration ratio for a pure liquid is equal to 1.

When

T₁=50°C=323.15K ⇒P₁=0.179

T₂=86°C=359.15K ⇒P₂=0.669

The Clasius-Clapeyron equation is:

$ln(\frac{P_2}{P_1}) =-\frac{AH_{vap}}{R} (\frac{1}{T_2}-\frac{1}{T_1})$

$ln(\frac{0.669}{0.179}) =-\frac{AH_{vap}}{8.3145 J.mol^{-1}K^{-1}} (\frac{1}{359.15K}-\frac{1}{323.15K})$

$1.3184 =-\frac{AH_{vap}}{8.3145 J.mol^{-1}K^{-1}} (-3.10186*10^{-4}K{^-1})$

ΔHvap=35339.5 J/mol=35.3395 KJ/mol

Normal boiling point ⇒ P=1 atm

Hence, we find the normal boiling point where:

T₁=323.15K

P₁=0.179 atm

P₂=1 atm

$ln(\frac{P_2}{P_1}) =-\frac{AH_{vap}}{R} (\frac{1}{T_2}-\frac{1}{T_1})$

$ln(\frac{1atm}{0.179atm}) =-\frac{35339.5 J/mol}{8.3145 J.mol^{-1}K^{-1}} (\frac{1}{T_2}-\frac{1}{323.15K})$

$1.7203=-4250.34 (\frac{1}{T_2}-\frac{1}{323.15K})$

T₂=371.77 K= 98.62 °C

5 0

3 years ago

When light is shown on a mixture of chlorine and chloromethane, carbon tetrachloride is one of the components of the final react

velikii [3]

A free-radical substitution reaction is likely to be responsible for the observations. The reaction mechanism of a reaction like this can be grouped into three phases:

Initiation; the "light" on the mixture deliver sufficient amount of energy such that the halogen molecules undergo homologous fission. It typically takes ultraviolet radiation to initiate fissions of the bonds.
Propagation; free radicals react with molecules to produce new free radicals and molecules.
Termination; two free radicals combine and form covalent bonds to produce stable molecules. Note that it is possible for two carbon-containing free-radicals to combine, leading to the production of trace amounts of long carbon chains in the product.

Initiation

$\text{Cl}-\text{Cl} \stackrel{\text{UV}}{\to} \text{Cl}\bullet + \bullet\text{Cl}$

where the big black dot indicates unpaired electrons attached to the atom.

Propagation

$\text{CH}_3\text{Cl}+ \text{Cl}\bullet \to \bullet\text{CH}_2\text{Cl} + \text{HCl}$

$\bullet\text{CH}_2\text{Cl} + \text{Cl}_2 \to \text{CH}_2\text{Cl}_2 + \text{Cl}\bullet$

$\text{CH}_2\text{Cl}_2 + \text{Cl}\bullet \to \bullet\text{CHCl}_2 + \text{HCl}$

$\bullet\text{CHCl}_2+ \text{Cl}_2 \to \text{CHCl}_3 + \bullet \text{Cl}$

$\text{CHCl}_3 + \text{Cl}\bullet \to \bullet\text{CCl}_3 + \text{HCl}$

$\bullet\text{CCl}_3 + \text{Cl}_2 \to \text{CCl}_4 + \text{Cl}\bullet$

Termination

$\text{Cl}\bullet + \bullet\text{Cl} \to \text{Cl}-\text{Cl}$

8 0

2 years ago

Which element in Group 17 is the most active nonmetal? (1) Br (2) I (3) Cl (4) F

Maksim231197 [3]

The element of the group 17 that is most active non metal is fluorine.

The group 17 of the periodic table contains bromine(Br), iodine(I), Chlorine(Cl) and fluorine(F).

Among all the elements of the group 17. Fluorine is the smallest in size.

Because of the small size of fluorine it has the highest electronegativity in group 17.

This high electronegativity makes it a very active non metal. It provides a very high oxidizing power and low dissociation energy to the fluorine atom.

Also because of the very small size the source of attraction between the nucleus and the electrons is very high in floor in atom.

It reacts readily to form oxides and hydroxides.

So, we can conclude here that fluorine is the most active non metal of group 17.

To know more about group 17, visit,

brainly.com/question/26440054

#SPJ4

7 0

7 months ago

What is a chemical off of the periodic table that is sticky

Alex73 [517]

I think it’s the one that has a Br

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