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Sonbull [250]
2 years ago
12

A gas occupies a 40.0 mL at 50 K. What volume does it occupy at 300K?

Chemistry
1 answer:
pickupchik [31]2 years ago
4 0

Answer:

B

Explanation:

Recall the ideal gas law:

\displaystyle PV = nRT

Because pressure and amount is kept constant while volume and temperature changes, we can rearrange the formula as:

\displaystyle \frac{V}{T} = \frac{nR}{P}

The right-hand side is simply some constant. In other words:

\displaystyle \frac{V_1}{T_1}= \frac{nR}{P} = \frac{V_2}{T_2}

Substitute in known values and solve:

\displaystyle \begin{aligned} \frac{(40.0\text{ mL})}{(50\text{ K})} & = \frac{V_2}{(300\text{ K})}\\ \\ V_2 & =240\text{ mL} \end{aligned}

In conclusion, our answer is B.

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