Question

A gas occupies a 40.0 mL at 50 K. What volume does it occupy at 300K?

Answer 1

Answer:

B

Explanation:

Recall the ideal gas law:

$\displaystyle PV = nRT$

Because pressure and amount is kept constant while volume and temperature changes, we can rearrange the formula as:

$\displaystyle \frac{V}{T} = \frac{nR}{P}$

The right-hand side is simply some constant. In other words:

$\displaystyle \frac{V_1}{T_1}= \frac{nR}{P} = \frac{V_2}{T_2}$

Substitute in known values and solve:

$\displaystyle \begin{aligned} \frac{(40.0\text{ mL})}{(50\text{ K})} & = \frac{V_2}{(300\text{ K})}\\ \\ V_2 & =240\text{ mL} \end{aligned}$

In conclusion, our answer is B.