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3 years ago

While John is traveling along a straight inter-

Physics

1 answer:

Juli2301 [7.4K]3 years ago

7 0

Answer:

83km

Explanation:

Distance from the 256km marker to 138km marker.....is (256 - 138) = 118km

Then when he traces back to the 173km marker....he moves (173 - 138) = 35km but its in the opposite direction...so hence..its -35km(since when calculating displacement...direction has to be accounted for)...

Total displacement from the 256km marker

; 118 + (-35) = 83km

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A circular conducting loop with a radius of 0.50 m and a small gap filled with a 10.0-Ω resistor is oriented in the xy-plane. If

saul85 [17]

Answer:

Current, I = 0.153 A

Explanation:

Given that,

Radius of the circular conducting loop, r = 0.5 m

Resistance of the resistor, $R=10\ \Omega$

Magnetic field, B = 1 T

Angle with z axis, $\theta=30^{\circ}$

Magnetic field increases to 10 T in 4 seconds

To find,

Magnitude of current.

Solve,

According to Faraday's law, the induced emf is given by:

$\epsilon=\dfrac{\phi_f-\phi_i}{t}$

$\phi_f\ and\ \phi_i$ are final flux and the initial flux respectively.

$\epsilon=NA\ cos\theta\dfrac{B_f-B_i}{t}$

$\epsilon=1\times \pi (0.5)^2\ cos(30)\dfrac{10-1}{4}$

$\epsilon=1.53\ V$

The magnitude of current can be calculated using the Ohm's law as :

$I=\dfrac{\epsilon}{R}$

$I=\dfrac{1.53}{10}$

I = 0.153 A

Therefore, the magnitude of the current that will be caused to flow in the loop is 0.153 A.

3 0

4 years ago

niobium metal becomes a superconductor when cooled below 9 k. its superconductivity is destroyed when the surface magnetic field

Furkat [3]

Niobium wire with a 2.60 mm diameter has a maximum current capacity of 500 A while still remaining superconducting.

<h3>Describe the present.</h3>

Current is the rate at which charge passes from one point on a circuit to another. In a circuit, a significant current flows when several coulombs or charge pass over the cross section of a wire. When the charge carriers are firmly packed inside the wire, high currents can be generated at low speeds.

<h3>What do current and electron actually mean?</h3>

Electron movement is referred to as electron current. The positive terminal receives electrons that are released by the negative terminal. Traditional current, usually referred to as just current, exhibits behavior consistent with positive charge carriers being the source of current flow. Regular current is received at the positive end and then flows to a negative terminal.

To know more about current visit:
brainly.com/question/15141911

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5 0

1 year ago

A baseball is projected horizontally with an initial speed of 18.1 m/s from a height of 1.85 m. at what horizontal distance will

gtnhenbr [62]

1) The motion of the baseball consists of two separate motions along the horizontal (x) and vertical (y) axis. The position on the two directions at time t is given by:
$x(t)=v_0t$
$y(t)=h- \frac{1}{2}gt^2$
where the motion on the x-axis is a uniform motion with constant speed $v_0=18.1 m/s$ , while the motion on the y-axis is a uniformly accelerated motion with constant acceleration $g=9.81 m/s^2$ , and initial height $h=1.85 m$ .

First of all, we can find the time t at which the ball reaches the ground by requiring $y(t)=0$ :
$0=h- \frac{1}{2}gt^2$
$t= \sqrt{ \frac{2h}{g} }= \sqrt{ \frac{2(1.85 m)}{9.81 m/s^2} }= 0.61 s$

and if now we substitute this time into the equation for x(t), we find the horizontal distance covered during this time interval, which is the horizontal distance covered by the ball before hitting the ground:
$x(t)=v_0 t=(18.1 m/s)(0.61 s)=11.04 m$

2) Speed of the ball as it hits the ground
We need to find the components of the velocity on the two directions, at the istant when the ball hits the ground.
On the x-axis, the velocity is the same as the initial one:
$v_x=18.1 m/s$
On the y-axis, the velocity is given by
$v_y(t)=gt$
If we substitute t=0.61 s (the time at which the ball reaches the ground), we find
$v_y =gt=(9.81 m/s^2)(0.61 s)=6.0 m/s$
And the speed of the ball is the magnitude of the resultant of the two components:
$v= \sqrt{v_x^2+v_y^2}= \sqrt{(18.1 m/s)^2+(6.0 m/s)^2}=19.1 m/s$

8 0

3 years ago

Read 2 more answers

Candace is curious about which brand of spot remover will best remove ketchup stains from her carpet. What is the dependent vari

slega [8]

This is a good know idk it

3 0

3 years ago

A 62.5 kg carpenter at a construction site plans to swing in a circular arc from one roof top to an adjacent roof at the end of

denis23 [38]

Answer:

v = 9.45 m/s

Explanation:

given,

mass of the carpenter = 62.5 Kg

length of rope = 13.4 m

Capable of exerting force = 1034 N

centripetal force acting on the body

$F = \dfrac{mv^2}{r}$

$F = \dfrac{62.5\times v^2}{13.4}$

F =4.664 v² N

Gravitational force on her =

F = m g

F = 62.5 x 9.81

F = 613.125 N

now,

4.664 v² + 613.125 = 1034

4.664 v² = 420.875

v² = 90.24

v = 9.45 m/s

Maximum speed which she can tolerate = v = 9.45 m/s

7 0

3 years ago