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galina1969 [7]
3 years ago
7

While John is traveling along a straight inter-

Physics
1 answer:
Juli2301 [7.4K]3 years ago
7 0

Answer:

83km

Explanation:

Distance from the 256km marker to 138km marker.....is (256 - 138) = 118km

Then when he traces back to the 173km marker....he moves (173 - 138) = 35km but its in the opposite direction...so hence..its -35km(since when calculating displacement...direction has to be accounted for)...

Total displacement from the 256km marker

; 118 + (-35) = 83km

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A child slides down a hill on a toboggan with acceleration of 1.8 m/s2. if she starts from rest, how far has she traveled in:
Stells [14]

A child slides down a hill on a toboggan with acceleration of 1.8 m/s2. if she starts from rest, how far has she traveled in: 2 seconds

Answer:

2.4 m

Explanation:

From the question above,

Applying equation of motion,

s = ut+at²/2....................... Equation 1

Where t = time, u = initial velocity, a = acceleration,  s = distance.

make s the subject of the equation,

Given: a = 1.8 m/s²,  t = 2 seconds, u = 0 m/s (from rest)

Substitute these value into equation 1

s = 0(2)+1.8(2²)/2

s = 1.2(4)/2

s = 2.4 m.

Hence she has traveled 2.4 m

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4 years ago
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tankabanditka [31]

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3 0
3 years ago
8. A rectangle is measured to be 6.4 +0.2 cm by 8.3 $0.2 cm.
mamaluj [8]

Answer:

a) The perimeter of the rectangle is 29.4 centimeters.

b) The uncertainty in its perimeter is 0.8 centimeters.

Explanation:

a) From Geometry we remember that the perimeter of the rectangle (p), measured in centimeters, is represented by the following formula:

p = 2\cdot (w+l) (1)

Where:

w - Width, measured in centimeters.

l - Length, measured in centimeters.

If we know that w = 6.4\,cm and l = 8.3\,cm, then the perimeter of the rectangle is:

p = 2\cdot (6.4\,cm+8.3\,cm)

p = 29.4\,cm

The perimeter of the rectangle is 29.4 centimeters.

b) The uncertainty of the perimeter (\Delta p), measured in centimeters, is estimated by differences. That is:

\Delta p = 2\cdot (\Delta w + \Delta l)  (2)

Where:

\Delta w - Uncertainty in width, measured in centimeters.

\Delta l - Uncertainty in length, measured in centimeters.

If we know that \Delta w = 0.2\,cm and \Delta l = 0.2\,cm, then the uncertainty in perimeter is:

\Delta p = 2\cdot (0.2\,cm+0.2\,cm)

\Delta p = 0.8\,cm

The uncertainty in its perimeter is 0.8 centimeters.

5 0
3 years ago
Science in the study of the natural world through. And.
Lyrx [107]
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6 0
3 years ago
Find a model for simple harmonic motion that has an initial displacement (t=0) of 0 inches, an amplitude of 5 inches, and a freq
Svetach [21]

Answer:

The equation of simple harmonic motion is y=5\sin{(8\pi t)}

Explanation:

Given that,

Amplitude = 5 inches

Frequency f= \dfrac{4}{3}

As per the question initial displacement is zero at t = 0 for sine curve.

The displacement is zero so the phase difference will be zero.

We know that,

The general equation of simple harmonic motion

y=A\sin(\omega t+\phi)

Where, A = amplitude

\omega = angular frequency

\phi = phase shift

We need to calculate the time period

Using formula of frequency

f=\dfrac{1}{T}

T=\dfrac{1}{f}

Put the value into the formula

T=\dfrac{1}{\dfrac{4}{3}}

T=\dfrac{3}{4}

We need to calculate the angular frequency

Using formula of angular frequency

\omega=\dfrac{2\pi}{T}

\omega=\dfrac{2\pi\times4}{3}

Put the value into the general equation

y=5\sin{(8\pi t)}

Hence, The equation of simple harmonic motion is y=5\sin{(8\pi t)}

7 0
3 years ago
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