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3 years ago

While John is traveling along a straight inter-

Physics

1 answer:

Juli2301 [7.4K]3 years ago

7 0

Answer:

83km

Explanation:

Distance from the 256km marker to 138km marker.....is (256 - 138) = 118km

Then when he traces back to the 173km marker....he moves (173 - 138) = 35km but its in the opposite direction...so hence..its -35km(since when calculating displacement...direction has to be accounted for)...

Total displacement from the 256km marker

; 118 + (-35) = 83km

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A child slides down a hill on a toboggan with acceleration of 1.8 m/s2. if she starts from rest, how far has she traveled in:

Stells [14]

A child slides down a hill on a toboggan with acceleration of 1.8 m/s2. if she starts from rest, how far has she traveled in: 2 seconds

Answer:

2.4 m

Explanation:

From the question above,

Applying equation of motion,

s = ut+at²/2....................... Equation 1

Where t = time, u = initial velocity, a = acceleration, s = distance.

make s the subject of the equation,

Given: a = 1.8 m/s², t = 2 seconds, u = 0 m/s (from rest)

Substitute these value into equation 1

s = 0(2)+1.8(2²)/2

s = 1.2(4)/2

s = 2.4 m.

Hence she has traveled 2.4 m

4 0

4 years ago

Please help I'm confused on where to start and with the graph.

tankabanditka [31]

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3 0

3 years ago

8. A rectangle is measured to be 6.4 +0.2 cm by 8.3 $0.2 cm.

mamaluj [8]

Answer:

a) The perimeter of the rectangle is 29.4 centimeters.

b) The uncertainty in its perimeter is 0.8 centimeters.

Explanation:

a) From Geometry we remember that the perimeter of the rectangle ( $p$ ), measured in centimeters, is represented by the following formula:

$p = 2\cdot (w+l)$ (1)

Where:

$w$ - Width, measured in centimeters.

$l$ - Length, measured in centimeters.

If we know that $w = 6.4\,cm$ and $l = 8.3\,cm$ , then the perimeter of the rectangle is:

$p = 2\cdot (6.4\,cm+8.3\,cm)$

$p = 29.4\,cm$

The perimeter of the rectangle is 29.4 centimeters.

b) The uncertainty of the perimeter ( $\Delta p$ ), measured in centimeters, is estimated by differences. That is:

$\Delta p = 2\cdot (\Delta w + \Delta l)$ (2)

Where:

$\Delta w$ - Uncertainty in width, measured in centimeters.

$\Delta l$ - Uncertainty in length, measured in centimeters.

If we know that $\Delta w = 0.2\,cm$ and $\Delta l = 0.2\,cm$ , then the uncertainty in perimeter is:

$\Delta p = 2\cdot (0.2\,cm+0.2\,cm)$

$\Delta p = 0.8\,cm$

The uncertainty in its perimeter is 0.8 centimeters.

5 0

3 years ago

Science in the study of the natural world through. And.

Lyrx [107]

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6 0

3 years ago

Find a model for simple harmonic motion that has an initial displacement (t=0) of 0 inches, an amplitude of 5 inches, and a freq

Svetach [21]

Answer:

The equation of simple harmonic motion is $y=5\sin{(8\pi t)}$

Explanation:

Given that,

Amplitude = 5 inches

Frequency $f= \dfrac{4}{3}$

As per the question initial displacement is zero at t = 0 for sine curve.

The displacement is zero so the phase difference will be zero.

We know that,

The general equation of simple harmonic motion

$y=A\sin(\omega t+\phi)$

Where, A = amplitude

$\omega$ = angular frequency

$\phi$ = phase shift

We need to calculate the time period

Using formula of frequency

$f=\dfrac{1}{T}$

$T=\dfrac{1}{f}$

Put the value into the formula

$T=\dfrac{1}{\dfrac{4}{3}}$

$T=\dfrac{3}{4}$

We need to calculate the angular frequency

Using formula of angular frequency

$\omega=\dfrac{2\pi}{T}$

$\omega=\dfrac{2\pi\times4}{3}$

Put the value into the general equation

$y=5\sin{(8\pi t)}$

Hence, The equation of simple harmonic motion is $y=5\sin{(8\pi t)}$

7 0

3 years ago